For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cut-off point with the y axis
On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

The given line is:

So we have:

We find 

So, a line perpendicular to the one given is of the form:

We substitute the given point to find "b":

Finally we have:

In point-slope form we have:

ANswer:

Explanation:
There are numerous videos and web sites that can show you the process of copying an angle. Some are animated. The best we can do here is show you a diagram with instructions. Of course, your curriculum materials already provide that.
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1. Set the compass to a convenient radius. Use that to draw an arc through rays ED and EF, using point E as the center.
2. Without changing the compass setting, draw a similar arc using S as the center, making sure it crosses the line containing S and extends far enough to accommodate the following steps. (In the attached, we show a full circle, because the tool we used won't draw an arc with a specific radius.)
3. Mark the points where the arc crosses ED as G, and where it crosses EF as H. Mark the point where the arc crosses the line containing S as I.
4. Set the compass radius to the distance GH. Using I as the center draw an arc with that radius so that it crosses the one made in step 2. Call that intersection point J. (Again, we have shown a circle because of the limitations of the tool being used for our diagram.)
5. Draw ray SJ to complete the angle copy.
Answer:
Both of your answers are correct.
Step-by-step explanation:
Expand the equations by distributing the number outside of the parentheses. After doing the expansion, your equations are both correct.
The line from the point to its reflection should be perpendicular.If we imagine a line from (5,7) to (2,2), it would have a slope of (2-7)/(2-5) = 5/3.
For that line to be perpendicular to y=-2/5x+6, their slopes should be each other's negative reciprocals.
-2/5 negative reciprocal is 5/2, which is not equal to our calculated 5/3, so (2,2) cannot be the reflected point. Evan was wrong.
Q1-74: AB have slope 6/5, C has -5/6, D 6/5, E -5/6 again.