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PSYCHO15rus [73]
3 years ago
11

Factor expression 9x^6- 16y^6

Mathematics
1 answer:
Darya [45]3 years ago
6 0
Using a^2-b^2 = (a-b)(a+b) you can factor the expression:
(3x^3-4y^3)(3x^3+4y^3)
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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t
nignag [31]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

m_ {1} * m_ {2} = - 1

The given line is:

5x-2y = -6\\-2y = -6-5x\\2y = 5x + 6\\y = \frac {5} {2} x + \frac {6} {2}\\y = \frac {5} {2} x + 3

So we have:

m_ {1} = \frac {5} {2}

We find m_ {2}:m_ {2} = \frac {-1} {\frac {5} {2}}\\m = - \frac {2} {5}

So, a line perpendicular to the one given is of the form:

y = - \frac {2} {5} x + b

We substitute the given point to find "b":

-4 = - \frac {2} {5} (5) + b\\-4 = -2 + b\\-4 + 2 = b\\b = -2

Finally we have:

y = - \frac {2} {5} x-2

In point-slope form we have:

y - (- 4) = - \frac {2} {5} (x-5)\\y + 4 = - \frac {2} {5} (x-5)

ANswer:

y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)

3 0
3 years ago
Read 2 more answers
Copy DEF to the line so that S is the vertex. This task will be complete when you have constructed an angle with vertex S that i
tino4ka555 [31]

Explanation:

There are numerous videos and web sites that can show you the process of copying an angle. Some are animated. The best we can do here is show you a diagram with instructions. Of course, your curriculum materials already provide that.

__

1. Set the compass to a convenient radius. Use that to draw an arc through rays ED and EF, using point E as the center.

2. Without changing the compass setting, draw a similar arc using S as the center, making sure it crosses the line containing S and extends far enough to accommodate the following steps. (In the attached, we show a full circle, because the tool we used won't draw an arc with a specific radius.)

3. Mark the points where the arc crosses ED as G, and where it crosses EF as H. Mark the point where the arc crosses the line containing S as I.

4. Set the compass radius to the distance GH. Using I as the center draw an arc with that radius so that it crosses the one made in step 2. Call that intersection point J. (Again, we have shown a circle because of the limitations of the tool being used for our diagram.)

5. Draw ray SJ to complete the angle copy.

4 0
3 years ago
Please help. I’ll mark you as brainliest if correct!
Alja [10]

Answer:

Both of your answers are correct.

Step-by-step explanation:

Expand the equations by distributing the number outside of the parentheses. After doing the expansion, your equations are both correct.

6 0
3 years ago
PLEASE HELP ME IN THESE TWO QUESTIONS ASAP! AND YES, I AM GOING TO MARK YOU AS THE BRAINLIEST ANSWER!!!!! 
Sladkaya [172]
The line from the point to its reflection should be perpendicular.If we imagine a line from (5,7) to (2,2), it would have a slope of (2-7)/(2-5) = 5/3.

For that line to be perpendicular to y=-2/5x+6, their slopes should be each other's negative reciprocals.

-2/5 negative reciprocal is 5/2, which is not equal to our calculated 5/3, so (2,2) cannot be the reflected point. Evan was wrong.

Q1-74: AB have slope 6/5, C has -5/6, D 6/5, E -5/6 again.
6 0
3 years ago
If a=8 and b=4, evaluate the following expression:3a+b​
hodyreva [135]

3(8) + 4

= 24 + 4

= 28

basically

7 0
2 years ago
Read 2 more answers
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