Question

Below are the average test scores of two different math class periods. Test 1 Test 2 Test 3 Test 4 Test 5 Test 6 83 87 82 89 4th period 90 82 90 85 6th period 86 81 88 How do the median test scores of each class period compare? OA. The median test score of 4th period is equal to the median test score of 6th period. B. The median test score of 4th period is greater than the median test score of 6th period. C. The median test score of 6th period is greater than the median test score of 4th period. D. The median test score of 6th period is greater than the median test score of 4th ​

Answer 1

You need to understand that you're solving for the average, which you already know: 90.

Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.

Solving for the average is simple

What is the average?

Add up all of the exam scores and divide that number by the number of exams you took.

(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.

Since you know you have that fourth exam, just substitute it into the total value as an unknown, X

(87 + 88 + 92 + X) / 4 = 90

Now you need to solve for X, the unknown

87+88+92+X4 /(4) = 90/ (4)

Multiplying for four on each side cancels out the fraction.

So now you have

87 + 88 + 92 + X = 360

This can be simplified as

267 + X = 360

Negating the 267 on each side will isolate the X value, and give you your final answer

X = 93

Now that you have an answer, ask yourself does it make sense.

I say that it does because there were two tests that were below average, and one that was just slightly above average.

To learn more about the average visit:

brainly.com/question/10428039

#SPJ1