Factor the following:
x^2 - 16 x + 63
The factors of 63 that sum to -16 are -7 and -9. So, x^2 - 16 x + 63 = (x - 7) (x - 9):
Answer: (x - 7) (x - 9)
It would be: 0.25 = 25/100 = 1/4
so, your answer is 1/4
5/6 hour = 5/6 × 60 = 300/6 = 50 minutes
8 tasks in 50 minutes
1 task = 50/8 = 6 1/4 minutes
a. robot completes task in 6 1/4 minutes
b. #tasks per hour =
#of tasks × time takes to do task < or = 60
n × 6.25 = 60
6.25n = 60.
n= 60/6.25 = 9.6
robot can complete 9 tasks in one hour
As per the problem
A jet flew for 2 hrs before strong head winds reduced its speed by 40 mph.
It took the plane 5 hrs to travel 1,380 miles
Total time=5 hrs, Time of fly before headwinds
,
Time of fly in headwinds
Let the speed before head winds 
Then speed in headwinds
As we know that

Hence using this formula and the given data we can write

Hence speed before flying into the headwinds=300mph
Because you can’t multiply 5x10 to get 1