Question

Which equation is the inverse of y = 16x² +1?

Answer 1

Answer:

$x = + - \sqrt{ \frac{y - 1}{16} }$

Step-by-step explanation:

$y - 1 = 16 {x}^{2} \\ \frac{y - 1}{16} = {x}^{2} \\ + - \sqrt{ \frac{y - 1}{16} } = {x} \\ x = + - \sqrt{ \frac{y - 1}{16} }$