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Viefleur [7K]
3 years ago
15

Kyle was given the following problem to solve.

Mathematics
2 answers:
jolli1 [7]3 years ago
7 0
no, they did not meet their goal.

Explanation:

gloves: $30

$30-$4=$26

$26*14=$364

bats: $90

$90-10%

10%=$9

$90-$9=$81

$81*9=$729

$364+$729=$1093

So, no, they did not reach they’re goal of selling $1200 worth of bats and gloves that week.

djyliett [7]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

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What is 0.0000007 in standard form
hoa [83]

Answer:

Step-by-step explanation:

Scientific form of 0.0000007 = 7 × 10^{-7}

8 0
3 years ago
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A clothes dryer having a wattage of 5000 watts is used for 25 hours each month. How many kilowatt hours of electricity does the
taurus [48]

Answer:20000

Step-by-step explanation:

30+1000+4000

5 0
3 years ago
Learning Task 4. Solve the problem by applying the sum and product of roots
Delvig [45]

Answer:

<em>Thus, the dimensions of the metal plate are 10 dm and 8 dm.</em>

Step-by-step explanation:

For a quadratic equation:

x^2+bx+c=0

The sum of the roots is -b and the product is c. Note the leading coefficient is 1.

We know the perimeter of the rectangular metal plate is 36 dm and its area is 80 dm^2. Being L and W its dimensions, then:

P=2(L+W)=36

A=L.W=80

Note both formulas are closely related to the roots of the quadratic equation, we only need to adjust the data for the perimeter to be exactly the sum of L+W and not double of it.

Thus we use the semi perimeter instead as P/2=L+W=18

The quadratic equation is, then:

x^2-18x+80=0

Factoring by finding two numbers that add up to 18 and have a product of 80:

(x-10)(x-8)=0

The solutions to the equation are:

x=10, x=8

Thus, the dimensions of the metal plate are 10 dm and 8 dm.

6 0
3 years ago
Can somebody plz help answer these questions correctly thanks so much :S
den301095 [7]

Answer:

29. p=8.6

30. r=12

31. m=13.6

32. n=12.4

33. x=9

34. y=2.7

Step-by-step explanation:

all u need to do is multiply the denominator to the number on the right

5 0
3 years ago
Read 2 more answers
In an exam, there is a problem that 60% of students know the correct answer. However, thereis 15% chance that a student picked t
SpyIntel [72]

Answer:

0.231

Step-by-step explanation:

Let the Probability of students that knew the correct answer be: P(A)

P(A) = 60% = 0.6

Let the Probability that the student picked the wrong answer even if he/she knows the right answer be: P(B)

P(B) = 15% =0.15

Let the Probability of the student that do not knew the correct answer Be P(C)

P(C) = 1 - P(A)

P(C) = 1 - 0.6

P(C) = 0.4

Let the Probability that the student does not know the right answer but guessed it correctly be: P(D)

P(D) = 25% = 0.25

Let the Probability that the student picked the right answer even if he/she knows the right answer be: P(E)

P(E) = 1 - P(B)

P(E) = 1 - 0.15

P(E) = 0.85

Probability that the student got the answer wrong = (0.60 X 0.15) + (0.40 X 0.75) = 0.39      

P( Student knew answer given he answered wrong) = \frac{P(Student knew answer) X P(Student answered wrong given he knew the answer}{0.39}

=\frac{0.6*0.15}{0.39}

=\frac{0.09}{0.39}

= 0.23076923077

= 0.231

6 0
4 years ago
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