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Solnce55 [7]
2 years ago
14

Factoring 8x^2-12x-8

Mathematics
2 answers:
Phantasy [73]2 years ago
8 0

Answer:

⇒ 4(x-2)(2x+1)

Step-by-step explanation:

1) Common factor

⇒ 8x^2-12x-8\\

⇒ 4(2x^2-3x-2)

2) Use the sum-product pattern

⇒ 4(2x^2-3x-2)

⇒ 4(2x^2+x-4x-2)

3) Common factor from the two pairs

⇒ 4(2x^2+x-4x-2)

⇒ 4(x(2x+1)-2(2x+1))

4) Rewrite in factored form

⇒ 4(x(2x+1)-2(2x+1))

⇒ 4(x-2)(2x+1)

Allushta [10]2 years ago
4 0

Answer:

( 8x - 4 ) ( x - 2 )

Step-by-step explanation:

8x² - 12x - 8

8x² - 16x + 4x - 8

8x ( x - 2 ) - 4 ( x - 2 )

<u>( 8x - 4 ) ( x - 2 )</u>

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