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Solnce55 [7]
1 year ago
14

Factoring 8x^2-12x-8

Mathematics
2 answers:
Phantasy [73]1 year ago
8 0

Answer:

⇒ 4(x-2)(2x+1)

Step-by-step explanation:

1) Common factor

⇒ 8x^2-12x-8\\

⇒ 4(2x^2-3x-2)

2) Use the sum-product pattern

⇒ 4(2x^2-3x-2)

⇒ 4(2x^2+x-4x-2)

3) Common factor from the two pairs

⇒ 4(2x^2+x-4x-2)

⇒ 4(x(2x+1)-2(2x+1))

4) Rewrite in factored form

⇒ 4(x(2x+1)-2(2x+1))

⇒ 4(x-2)(2x+1)

Allushta [10]1 year ago
4 0

Answer:

( 8x - 4 ) ( x - 2 )

Step-by-step explanation:

8x² - 12x - 8

8x² - 16x + 4x - 8

8x ( x - 2 ) - 4 ( x - 2 )

<u>( 8x - 4 ) ( x - 2 )</u>

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P=2L+2H
First, isolate 2H:
2H=P-2L
Second, get a singular value of H (just H):
2H/2=(P-2L)/2

Final answer: 

H=\frac{P-2L}{2}
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2 years ago
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The whole numbers from 10-12 are paired with their factors explain why this pairing doesnt describe a function
myrzilka [38]

Answer:

As given whole numbers from 10 - 12 are paired with their factors.

factor of ,10=1,2,5,10 → (10,1),(10,2),(10,5)(10,10)

factor of 11=1, 11 → (11,1),(11,11)

factor of 12=1,2,3,4,6,12→ (12,1),(12,2),(12,3),(12,4),(12,6),(12,12)

As we know for an ordered pair to be function Every element in the domain must have a unique image, i.e it can't have more than one image.

→ As element 10, have four images,which are 1,2,5,10 so it can,t be a function.

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8 0
3 years ago
Let f(x)=-x-7 find f(-6)
pashok25 [27]

Answer:

x=6f-7 is the correct answer.

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3 years ago
2. If a= 2, b= 3 and c= 3,evaluate: i) a+ 2b ii) a+b+c​
scoundrel [369]

Answer:

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7 0
2 years ago
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Answer:

x = 14/3

Step-by-step explanation:

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Distribute

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Subtract 4x

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Add 44 to each side

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Divide each side by 12

12x/12 = 56/12

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3 years ago
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