Which of the following is an extraneous solution of √4x+41 = x+5?
1 answer:
Answer:
x=-8
Step-by-step explanation:
on squaring both sides
either x-2=0 or x+8=0
either x=2 or x=-8
Putting x=2 in original equation, we get
7=7 hence, it is not an extraneous solution
Putting x=-8 in original equation
i.e. 3=-3
Hence, x=-8 is an extraneous solution (since it doesn't satisfy the original equation)
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