Let distance form the pole = x and height of the hill = y ft
now we can set up 2 equayions
tan 18 = (40-y)/x
tan 14 = y/x
from second equation y = sxtan14 so we have:-
tan 18 = ( 40 - x tan 14) / x
x tan 18 = 40 - x tan 14
x(tan 18 + tan 14) = 40
x = 40 / (tan18 + tan 14) = 69.66 feet Answer
93,000 is the correct answer
The ratios are both identical
sin x = perpendicular/hypotenuse = 3/5
cosy = base/hypotenuse = 3/5
Answer:
<em>Rajan must use </em><em>0.75</em><em> liters of 5% hydrochloric acid solution and </em><em>0.25</em><em> liters of 45% hydrochloric acid solution.</em>
Step-by-step explanation:
Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.
As Rajan need total of 1 liter of solution, so
i.e
--------------------1
As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

i.e
-------------2
Putting value of x from equation 1 in equation 2,





Putting the value of y in equation 1,

Therefore, Rajan must use 0.75 liters of 5% hydrochloric acid solution and 0.25 liters of 45% hydrochloric acid solution.
Answer: 2 seconds
Step-by-step explanation:
got it right