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2 years ago

Triangle P Q R is shown. Angle Q P R is a right angle. The length of Q P is 8 StartRoot 3 EndRoot and the length of P R is 8.

Mathematics

1 answer:

Vika [28.1K]2 years ago

6 0

Answer: Length of side QR is 16 units.

Step-by-step explanation: Given that dimensions of PQR

QPR= 90degrees

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Segment PE has endpoints P(-4,4) and E(0,-4). Find the coordinates of point Q such that PQ:QE is 1:3. Enter the coordinates belo

Natalka [10]

Answer:

(-3, 2)

Step-by-step explanation:

Given that point Q, partitions segment PE, such that PQ:QE is 1:3, coordinates of point Q is found using the formula below:

$x = \frac{mx_2 + nx_1}{m + n}$

$y = \frac{my_2 + ny_1}{m + n}$

Where,

$P(-4, 4) = (x_1, y_1)$

$E(0, -4) = (x_2, y_2)$

$m = 1, n = 3$

Plug in the necessary values to find x and y coordinates for point Q as follows:

$x = \frac{mx_2 + nx_1}{m + n}$

$x = \frac{1(0) + 3(-4)}{1 + 3}$

$x = \frac{0 - 12}{4}$

$x = \frac{-12}{4}$

$x = -3$

$y = \frac{my_2 + ny_1}{m + n}$

$y = \frac{1(-4) + 3(4)}{1 + 3}$

$y = \frac{-4 + 12}{4}$

$y = \frac{8}{4}$

$y = 2$

The coordinates of the point Q are (-3, 2))

8 0

3 years ago

V=1/3 Bh, for h A. h= 3V/B B. h=B/3V C. h=V/3B D.h=3B/V

Basile [38]

Answer:

A. h=3v/b

Step-by-step explanation:

v=1/3bh

1) divide by b

v/b=1/3h

2) multiply reciprical

3v/b=h

h=3v/b

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3 years ago

You walk at a speed of 1.429m/s. How far could you walk in 10 MINUTES? Show your work!

arsen [322]

Answer:

Well the answer is 857.4 meters per minute

Step-by-step explanation:

The reason is because 1.429 times 60= 85.74 That means that you walk 85.74 meters per second. Then that times 10 is 857.4 . Can I get brainliest

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3 years ago

What is - 8/41 as a repeating decimal?

ss7ja [257]

Answer:

-0.(19512) = -19512/99999

Step-by-step explanation:

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Alison wants to construct the perpendicular bisector of MN¯¯¯¯¯¯¯. What should Alison do for her first step? A.) Place the point

swat32

option A is correct for construction of perpendicular bisector of MN alison has to Place the point of the compass on point M and draw an arc, using a width for the opening of the compass that is equal to 1/2MN on both sides and then join arcs by straight line

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3 years ago

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