An=a1+d(n-1)
a1=first term
d=common differnce
easy
inptu 4 for n and 10
a4=5+(4-1)1/2
a4=5+3(1/2)
a4=5+3/2
a4=6 and 1/2
4th term is 6 and 1/2
10th term
a10=5+(10-1)1/2
a10=5+(9)1/2
a10=5+9/2
a10=9 and 1/2
4th term is 6 and 1/2
10th term is 9 and 1/2
Step-by-step explanation:
a) f(1) = -1 → x = -1
b) g(1) = Undefined
c) f(x) = 1 → x= Undefined
d) g(x) = 1 → x= 5
From the given ordered pair representing Jacinda's progress, her speed is equal to 10 miles per hour. Letting x be the time it takes for Jacinda to catch up with Raj, the total distance Raj would travel is
1.5 + 4.5x
and Jacinda's total distance is 10x. Mathematically,
1.5 + 4.5x = 10x
The value of x from the equation is 0.27 hours. Therefore, Jacinda needs to run 2.7 miles to catch up with Raj.
Start with assigning each person with a variable to represent their height
Ebi: e
Jose: j
Derell: d
Asami: a
Ebi'd height was 2.5 cm greater than Jose's height
j + 2.5 = e
Jose's height was 3.1 cm greater than Derell's
d + 3.1 = j
Derell's height is 0.4 cm less than Asami's height
a - 0.4 = d
Ebi is 162.5 cm tall
e = 162.5
So, plug in 162.5 into any of the above equations were there is a variable of e
j + 2.5 = e
j + 2.5 = 162.5
Subtract 2.5 from both sides of the equation
j = 160 cm
Jose's height is 160 cm
Now, plug in 160 into any of the above equations where there is a j
d + 3.1 = j
d + 3.1 = 160
Subtract 3.1 from both sides of the equation
d = 156.9 cm
Derell's height 156.9 cm
so, plug in 156.9 into any of the above equations where there is a d
a - 0.4 = d
a - 0.4 = 156.9
Add 0.4 on both sides of the equation
a = 157.3 cm
Asami's height is 157.3 cm
