Angles ∠ACD and ∠CAB are congruent because they are alternate angles. Then the area of the triangle AOB will be 22.53 square cm.
<h3>What is the
area of the right-angle triangle?</h3>
The area of the right-angle triangle is given as
A = 1/2 x B x H
Where B is the base and H is the height of the right triangle.
We know that angles ∠ACD and ∠CAB are congruent because they are alternate angles.
α₁ = 40°
AO = OC = 7.8 cm
Then the area of the triangle will be
Area = 1/2 x 7.8 x 7.8 x tan40°
Area = 22.53 square cm
More about the area of the right-angle triangle link is given below.
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Answer:
General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Chain Rule]: ![\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<u>Step 2: Differentiate</u>
- Logarithmic Differentiation [Derivative Rule - Chain Rule]:
- Trigonometric Differentiation [Derivative Rule - Chain Rule]:
- Basic Power Rule:
- Rewrite [Trigonometric Identities]:
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
1) Point-slope form
(y-y1)=m(x-x1)
m= - 3,
point (3,-4), so x1 = 3, y1 = - 4.
(y+4)= -3(x- 3)
2)Point-slope form
(y-y1)=m(x-x1)
m= - 3/4,
point (4,5), so x1 = 4, y1 = 5.
(y-5)= - 3/4(x-4)
Answer:
D the last one
Step-by-step explanation:
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