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ira [324]
2 years ago
11

Morgan wants to draw a right triangle two side lengths are 6 unites and 8 units. select all the possible dimensions of the third

side
2 units 14 units
28units 10 units
√28 units
Mathematics
1 answer:
olga_2 [115]2 years ago
5 0

The possible dimension of the third side is 10 units.

<h3>What is the possible dimension of the third side?</h3>

A right triangle is a triangle that has three sides known as the opposite, adjacent and hypotenuse. The hypotenuse is the longest sides of the triangle. The opposite side is the side that faces an angle. The adjacent side is the third side.

If two side lengths are given, the third side can be determined using the Pythagoras theorem.

√a² + b ² = c

√6² + 8² = √36 + 64 = 10 units

To learn more about right angled triangle, please check: brainly.com/question/20694080

#SPJ1

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alekssr [168]

Answer:

Option A

Step-by-step explanation:

We will simplify the expressions given in the options first,

x² - 16 = (x - 4)(x + 4)

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Option A

\frac{x^2-16}{2x+8} × \frac{x+4}{x^2+8x+16}

= \frac{(x+4)(x-4)}{2(x+4)}\times \frac{(x+4)}{(x+4)^2}

= \frac{x-4}{2(x+4)}

Option B

\frac{2x+8}{x^2-16} ÷ \frac{x^2+8x+16}{x+4}

= \frac{2(x+4)}{(x+4)(x-4)} ÷ \frac{(x+4)^2}{(x+4)}

= \frac{2}{(x-4)}\times \frac{1}{(x+4)}

= \frac{2}{x^2-16}

Option C

\frac{x^2-16}{2x+8} ÷ \frac{x+4}{x^{2}+4x+16}

= \frac{(x-4)(x+4)}{2(x+4)}\times \frac{(x+4)^2}{(x+4)}

= \frac{(x-4)(x+4)}{2}

Option D

\frac{2x+8}{x^2-16}\times \frac{x^2+8x+16}{x+4}

= \frac{2(x+4)}{(x-4)(x+4)}\times \frac{(x+4)^2}{(x+4)}

= \frac{2(x+4)}{(x-4)}

Therefore, Option A is the answer.

6 0
3 years ago
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Step-by-step explanation:

think rise over run!

rise = 4

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since the slope is going downwards we know it's negative

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3 0
3 years ago
Read 2 more answers
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The Normal approximation to the binomial 

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∴ BC = 10² - 5²

= 100 - 25 = 75

BC = √75 unit

7 0
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