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kompoz [17]
2 years ago
8

find two consecutive even integers such that five times the first integer is equal to four times the second integer​

Mathematics
2 answers:
drek231 [11]2 years ago
5 0

Answer:

8 and 10

Step-by-step explanation:

All you need to know to begin setting this up is that to get from one even integer to the next consecutive even integer, add 2.

Start with  x = an even integer (yes, because you say so!)

Next even integer = x + 2

"five times the first integer is equal to four times the second integer"

5x = 4(x + 2)

Distribute the 4.

5x = 4x + 8

Subtract 4x

x = 8

The two integers are 8 and 10

5(8) = 4(10) as desired!

Nadya [2.5K]2 years ago
4 0

Answer:

  8 and 10

Step-by-step explanation:

"Five times the first is equal to 4 times the second" means the ratio of the smaller to larger is 4 : 5.

__

Those ratio units differ by 1. You want two numbers that differ by 2, so you can get them by multiplying these ratio values by 2:

  4 : 5 = 8 : 10

Your two numbers are 8 and 10.

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Simplify the expression: 2x - 14x + 7
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for every girl taking classes at the martial arts schools there are 3 boys who are taking classes at the school. if there are 23
Yuliya22 [10]

You have to be very careful how you set this up. For every girl (who counts as 1) there are 3 boys (who count as 3). The total number in the proportion is 3 + 1 =4. You are given a total, but that is both boys and girls. That's why you need the 4.

3/4 = x / 236 Cross multiply

4x = 3 * 236

4x = 708 Divide by 4

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x = 177

There are 177 boys at the school and 236 - 177 = 59 girls.

3 0
3 years ago
Which symbol makes 3 13/28 and 3 17/30 a true sentence
mixas84 [53]

Answer:

Step-by-step explanation:

<em>13/28 = 195/420</em>

<em>17/30 =  238/420</em>

<em />

<em>So that means that 3 17/30 > 3 13/28</em>

3 0
4 years ago
Two different simple random samples are drawn from two different populations. The first sample consists of 20 people with 9 havi
QveST [7]

Answer: (-0.48,\ -0.04)

Step-by-step explanation:

The confidence interval for the difference of two population proportion is given by :-

(p_1-p_2)\pm z_{\alpha/2}\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}

Given : The first sample consists of 20 people with 9 having a common attribute.

Here, n_1=20 , p_1=\dfrac{9}{20}=0.45

n_2=2100 , p_1=\dfrac{1492 }{2100}\approx0.71

Significance level : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

A 95% confidence interval for the difference of two population proportion will be :-

(0.45-0.71)\pm z_{\alpha/2}\sqrt{\dfrac{0.45(1-0.45)}{20}+\dfrac{0.71(1-0.71)}{2100}}\\\\\approx -0.26\pm0.22\\\\=(-0.26-0.22,-0.26+0.22)\\\\=(-0.48,\ -0.04)

3 0
4 years ago
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