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N76 [4]
3 years ago
9

The minimum mark to obtain a Grade A is 75. Cheryn managed to achieve an average of Grade A for three of her English quizzes. Wh

at is the minimum mark she scored in her first quiz if scored 76 and 89 marks in her second and third quiz, respectively?​
Mathematics
1 answer:
Masteriza [31]3 years ago
4 0

9514 1404 393

Answer:

  60

Step-by-step explanation:

Let m represent the mark Cheryn scored on her first quiz. Then her average is ...

  (m +76 +89)/3 ≥ 75

  m +165 ≥ 225 . . . . . . . . multiply by 3

  m ≥ 60 . . . . . . . . . . . . subtract 165

Cheryn scored a minimum of 60 marks on her first quiz.

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Alex wrote 103.903 in expanded form as 100+3x1+9x1/100+3x1/1000. Explain his mistake. Then tell how to correct it.
masya89 [10]
Here is the mistake is on 9x1/100 because after decimal 9 is there means
9 has to be multiplied by 1/10 to get the 0.9

Here if we expand the 103.903 then from left to right
1 = 1x100 +
0 = 0x10   +
3 = 3x1     +
9 = 9x1/10+
0 = 0x1/100+
3 = 3x1/1000 = 103.903
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3 years ago
Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).
bagirrra123 [75]

Answer:

27\pi \ cm^{2}

Step-by-step explanation:

we know that

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we have

r=6\ cm

substitute

A=\pi (6)^{2}=36 \pi\ cm^{2}

Remember that a central angle of 360\° subtends for the area of a complete circle

so

by proportion

Find the area of the circle for a central angle of 270\°

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5 0
3 years ago
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How can I solve this proof?? PLZ HELP I DONT UNDERSTAND!! Thanks !!
love history [14]

Hello from MrBillDoesMath!

Answer:

See below


Discussion:

Triangles BAD and BCD are congruent by the SAS postulate.

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          * Angle ADB and CDB are both right angles, and hence equal, because

            BD is the perpendicular bisector of AC)


Corresponding parts of congruent triangles are equal so angle BAD = angle BCD,  which was to be proven.


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8 0
3 years ago
Simplify 3/5(10g-5k)-(-3g+2k)
dybincka [34]

Answer:

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Step-by-step explanation:

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makkiz [27]
♥ Let's solve:

15n+5n can be known as 15+5.

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Final answer: 20n
6 0
3 years ago
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