A line parallel to y=2x+4 that contains the point (3,-2) is y=2x-8. The line is parallel because it has the same slope as AB, and we can find the intercept by plugging in (3,-2) into slope-intercept form and solving for b.
Rate of interest is given as 6% and Principle amount as Rs2000
Interest after 1 year= P*R*T/100 = 2000*6*1/100 = Rs 120
Net amount at the end of first year= Principle+ interest-Amount withdrawn=2000+120-700= Rs 1420
For the next 2 years, simple interest will be paid at the rate of 6% on the amount of Rs 1420 which is = 1420*6*2/100 =Rs 170.40
Balance after 3 years= 1420+170.40=Rs 1590.40
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Answer:
4 x 4 = 16, 16 divided by 2 ( x 1/2 ) = 8
8 x 2 = 16(area of two triangles)
8 x 4 = 32(area of base below)
5.7 x 8 = 45.6 (area of slant)
4 x 8 = 32(area of the rectangle behind the figure)
Add all the given areas:
16 + 32 + 45.6 + 32 = 125.6 in^2 is your answer
It will take him five days to paint 3/4 of the fence.
a) If this trend continues, how many birds will be left by 2010 will be 525
b) The birds would there have been in 1990 will be 2475
<h3>What is rate of increase?</h3>
Rate of increase or decrease is defined as the increment or decrement in any quantity over a period of time constantly.
Here we have the data that:
There were 1500 birds in 2000 and they are decreasing at an annual rate of 6.5%.
a) If this trend continues, how many birds will be left by 2010
{1500x6.25}/{100}=97.5
So the bird decrement in the one year will be =97.5 so it will be in the 10 years or upto 2010 will be
97.5x10=975
So the birds left till 2010 will be:
Q=1500-975=525
b)The birds would there have been in 1990 will be:-
=1500+975=2475
Hence If this trend continues, how many birds will be left by 2010 will be 525.The birds would there have been in 1990 will be 2475
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