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3 years ago

What is x 8(3x+6)=168

Mathematics

2 answers:

Murljashka [212]3 years ago

4 0

Answer:

x=-5

Step-by-step explanation:

24x+48=168

24x-120

x=5

8(15+6)=168

120+48=168

168=168

suter [353]3 years ago

4 0

Answer: 5

Step-by-step explanation: 8 (3x+6)= 168/ 8 (3 x5+6)= 168; so 8(3x5+6)=168

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Find f such that the given conditions are satisfiedf’(x)=x-4, f(2)=-1

kicyunya [14]

Given:

$f^{\prime}\left(x\right)=x-4,\text{ and}f\left(2\right)=-1$

To find:

The correct function.

Explanation:

Let us consider the function given in option D.

$f(x)=\frac{x^2}{2}-4x+5$

Differentiating with respect to x we get,

$\begin{gathered} f^{\prime}(x)=\frac{2x}{2}-4 \\ f^{\prime}(x)=x-4 \end{gathered}$

Substituting x = 2 in the function f(x), we get

$\begin{gathered} f(2)=\frac{2^2}{2}-4(2)+5 \\ =2-8+5 \\ =-6+5 \\ f(2)=-1 \end{gathered}$

Therefore, the given conditions are satisfied.

So, the function is,

$f(x)=\frac{x^{2}}{2}-4x+5$

Final answer: Option D

6 0

2 years ago

The difference of the square of a number and 12 is equal to 4 times that number. find the negative solution.

dybincka [34]

Im sorry but Im not sure

4 0

3 years ago

Find the equation of the line that passes through the points (12,21) and (46,33). V.35r-162

AnnZ [28]

Answer:

the answer is Y=(6/17)X + (285/17)

Step-by-step explanation:

1. Identify the X and Y coordinate of each point.

for example, the first point could be (12,21), therefore X1 = 12 and Y1 = 21 and the second point is then (46,33), therefore X2 = 46 and Y2 = 33

2. to find the equation of the line it is necessary to find the slope.

knowing that the equiation of the slope is M = Y2-Y1/X2-X1 we replace

$m=\frac{33-21}{46-12}=\frac{12}{34}$ and then we simplify the result to $\frac{12}{34}$

3. Using the Point-slope equation which is Y-Y1=M(X-X1) we replace

$Y-33=\frac{6}{17}(X-46)$

$Y=\frac{6}{17}X-\frac{276}{17}+33$

$Y=\frac{6}{17}X+\frac{285}{17}$

7 0

3 years ago

What is the slope of the line that passed through the points (8,6) and (-2, 10)

lbvjy [14]

Slope: -4/10 = 4/-10

Work: y2-y1/x2-x1

1) 10-6/-2-8

2)4/-10

8 0

3 years ago

the third term and the fifth term of a geometric progression are 2 and 1/8 respectively. If all terms are positive, find the sum

loris [4]

Answer:

42 + 2/3

Step-by-step explanation:

First, to calculate the sum of an infinite geometric series, our formula is

a₁/(1-r), with a₁ being the first term of the series and r being the common ratio. Therefore, we want to find both a₁ and r.

To find r, we can first determine that 2 * r = a₄ and a₄ * r = a₅, as the ratio separates one number from the next in a geometric series. Therefore, we have

2 * r * r = a₅

2 * r² = 1/8

divide both sides by 2 to isolate the r²

r² = 1/16

square root both sides to isolate r

r =± 1/4. Note the ± because r²=1/16 regardless of whether r = 1/4 or -1/4. However, because all terms are positive, r must be positive as well, or a₄, for example, would be 2 * (-1/4) = -0.5

Therefore, r = 1/4 .

To find the first term, we know that a₁ * r = a₂, and a₂ * r = a₃. Therefore, a₁ * r² = a₃ = 2

a₁ * 1/16 = 2

divide both sides by 1/16 to isolate a₁

a₁ = 2 * 1/ (1/16)

= 2 * 16

= 32

Plugging a₁ and r into our infinite geometric series formula, we have

a₁/(1-r)

= 32 / (1-1/4)

= 32/ (3/4)

= 32/ 0.75

= 42 + 2/3

3 0

3 years ago