Question

RATIONAL EXPONENTS pls help what do i do??

Answer 1

Answer:

x = 3

Step-by-step explanation:

$26=-1+\left( 27x\right)^{\frac{3}{4} }$

$\Longleftrightarrow 27=\left( 27x\right)^{\frac{3}{4} }$

$\Longleftrightarrow \left( 27\right)^{\frac{4}{3} } =\left[ \left( 27x\right)^{\frac{3}{4} } \right]^{\frac{4}{3} }$

$\Longleftrightarrow \left( 27\right)^{\frac{4}{3} } =\left( 27x\right)^{\frac{3}{4} \times \frac{4}{3} }$

$\Longleftrightarrow \left( 27\right)^{\frac{4}{3} } =27x$

$\Longleftrightarrow x=\frac{27^{\frac{4}{3} } }{27}$

$\Longleftrightarrow x=27^{\frac{4}{3} -1}$

$\Longleftrightarrow x=27^{\frac{1}{3} }$

$\Longleftrightarrow x=\sqrt[3]{27}$

$\Longleftrightarrow x=3$

Answer 2

Answer:

x = 3

Step-by-step explanation:

• $26=-1+(27x)^{\frac{3}{4}}$

• $\implies 26+1=27^{\frac{3}{4}} x^{\frac{3}{4}}$

• $\implies 27\div 27^{\frac{3}{4}} =x^{\frac{3}{4}}$

• $\implies 27^{1-\frac{3}{4}} =x^{\frac{3}{4}}$

• $\implies 27^{\frac{4-3}{4}} =x^{\frac{3}{4}}$

• $\implies 27^{\frac{1}{\cancel 4}} =x^{\frac{3}{\cancel 4}}$

• $\implies 27 =x^{3}$

• $\implies 27^{\frac{1}{3}} =x$

• $\implies (3^3)^{\frac{1}{3}} =x$

• $\implies x = 3$