We just need to count the number of outcomes that have exactly one even number. The total number of outcomes is 36. We see that from the first row, the number of outcomes that qualify are 3: 1-2, 1-4, 1-6 (out of the 6 total outcomes). For the 2nd row, again there are 3: 2-1, 2-3, 2-5. It is obvious by now that for any row, whether the number is even or odd, there are 3 outcomes on that row that correspond to rolling exactly one even number. Hence, there are in total 6*3=18 favorable outcomes.
Answer:11
It is 11 because the lines beside the numbers represent ABSOLUTE VALUE. Absolute value basically means that wether or not it is a positive or negative number it will always be positive. Simplify-6+5=11
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Answer:
Explanation:
Use the Pythagorean theorem (
a
2
+
b
2
=
c
2
)
Lets label the right triangle such that:
a
=
12
b
=
16
c
=
x
Thus,
12
2
+
16
2
=
x
2
144
+
256
=
x
2
400
=
x
2
√
400
=
x
20
=
x
So our missing side,
c
is
20
We can now say that the sides of our triangle are
12
,
16
,
20
I've included a link that lists a couple of Pythagorean triples (a couple because they are infinitely many).
Step-by-step explanation:
Hope it helpful
Answer:
a.) f(x) = 
where 90 < x < 120
b.) 
c.)
d.) 
Step-by-step explanation:
Let
X be a uniform random variable that denotes the actual charging time of battery.
Given that, the actual recharging time required is uniformly distributed between 90 and 120 minutes.
⇒X ≈ ∪ ( 90, 120 )
a.)
Probability density function , f (x) = 
where 90 < x < 120
b.)
P(x < 110) = 
= ![\frac{1}{30}[x]\limits^{110}_{90} = \frac{1}{30} [ 110 - 90 ] = \frac{1}{30} [ 20] = \frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B30%7D%5Bx%5D%5Climits%5E%7B110%7D_%7B90%7D%20%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%20110%20-%2090%20%5D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%2020%5D%20%3D%20%5Cfrac%7B2%7D%7B3%7D)
c.)
P(x > 100 ) = 
= ![\frac{1}{30}[x]\limits^{120}_{100} = \frac{1}{30} [ 120 - 100 ] = \frac{1}{30} [ 20] = \frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B30%7D%5Bx%5D%5Climits%5E%7B120%7D_%7B100%7D%20%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%20120%20-%20100%20%5D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%2020%5D%20%3D%20%5Cfrac%7B2%7D%7B3%7D)
d.)
P(95 < x< 110) = 
= ![\frac{1}{30}[x]\limits^{110}_{95} = \frac{1}{30} [ 110 - 95 ] = \frac{1}{30} [ 15] = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B30%7D%5Bx%5D%5Climits%5E%7B110%7D_%7B95%7D%20%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%20110%20-%2095%20%5D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%2015%5D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
