Answer:
When there are 5 molecules of fructose on each side of the membrane.
Explanation:
The solution will reach equilibrium fro fructose when there are 5 molecules of fructose on each side of the membrane.
A membranous system is said to be at equilibrium when there are equal concentration of a particular molecule on both sides of the membrane.
<em>Hence, for a membranous system with 10 molecules of fructose on one side, an equilibrium can only be reached for fructose when there are 5 molecules on one side and the remaining 5 molecules on the other side. </em>
The most observable difference is the way in which cytokinesis occurs. In plants a new cell wall is fashioned between the new daughter cells, while in animal cells the cell membrane constricts to pinch the parent cell into daughter cells.
Answer:
This can be explained based on structure, and on metabolisms of carbohydrate.
Explanation:
Carbohydrate has a relatively simple structural composition than the either protein or fatty acids. The C, H and Oxygen molecules are of relatively fewer in number and few chains than fats and protein.Thus cells will spend less energy to break bonds(catabolisims) among these molecules during cellular respiration pathways to trap the energy.
In addition glucose the end products of carbohydrate did not need any processing before it enters glycolysis, Kreb's Cycle and oxidative phosphorylation pathways to generate energy for the cells.
Conversely, for protein to be used it has to be first deaminated(removal of amino acid) by the liver before it enters glycolysis,while fats needs to be broken down and undergo beta oxidation with the long chains removed before it can form acetyl CoA. Therefore cells will prefer few steps, less endergonic pathways of glucose than longer more endergonic amino acids and fatty acid pathways.
Furthermore, glucose can be used in cellular respiration to produce energy either aerobically or anaerobically, while fats can only be used anaerobically. Therefore, since cells usually prefer to thrive in aerobic conditions they breakdown glucose easily during this period, and when lack of oxygen occurs they switched to anaerobic, Thus, the versatility of glucose to oxygen concentration makes glucose a better choice. Besides if fats was used anaerobically, ketone bodies build up which may be toxic to the cells.
Density <span>water allows large organisms like the blue whale to swim in the ocean and not be crushed by their body weight.</span>
