$2x - 2y = 24 \\ 2(x - y) = 24 \\ x = 12 + y......eq(1) \\ 4x + 7y = - 40......eq(2) \\ substituting \: the \: value \: of \: x \: in \: eq(2) \\ 4(12 + y) + 7y = - 40 \\ 48 + 4y + 7y = - 40 \\ 11y = - 40 - 48 \\ y = \frac{ - 88}{11} \\ y = - 8 \\ putting \: the \: value \: of \: y \: im \: eq(1) \\ x = 12 - 8 \\ = 4$

Step-by-step explanation:

3x-2y=24......eqi

x+2y=48........eqii

now solving eq i&ii

4x=72

x=72/4

x=18

now putting the value of x in eqii

18+2y=48

2y=48-18

y=30/2

y=15

7 0

3 years ago

Please help! Also please make sure you include a let statement :) Thank you

nata0808 [166]

Answer:

this is more than one question

Step-by-step explanation:

4 0

3 years ago

IF A, B, C are three mutually exclusive events with 1/3p(A)=2/3p(B)=1/6P(C).

Bas_tet [7]

A=2(67.76).45 it’s ten divided by 8

7 0

3 years ago