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olga_2 [115]
3 years ago
10

Xy'+xy^2=y ??????????

Mathematics
1 answer:
valkas [14]3 years ago
4 0
I believe it is -1.....It is probbaly wrong but give it a try...
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What's the value of x when f(x)=58
Natalka [10]
Infinite, because essentially the graph is going to have a horizontal line because f(x)=58/y=58 just means that the y will remain on 58 but the x can have whatever value.
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A number cube has sides numbered 1 through 6. The probability of rolling a 2 is 16
ser-zykov [4K]
Hello there.

<span>A number cube has sides numbered 1 through 6. The probability of rolling a 2 is 16
what is the probability of not rolling a 2?

Answer: I'm guessing that by 16 you meant 1/6. Therefore you do 6/6 - 1/6 = 5/6,
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3 0
3 years ago
Read 2 more answers
Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

8 0
3 years ago
21-x=13 telllllllllll mee​
BaLLatris [955]

Answer:

x = 8

Step-by-step explanation:

21-x=13 \\ x = 21 - 13 \\ x = 8

4 0
3 years ago
Read 2 more answers
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