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taurus [48]
2 years ago
5

Solve 5x^2=180 algebraically

Mathematics
2 answers:
Tom [10]2 years ago
7 0

Hi...

<h3>Given:</h3>

\texttt{5x}² \texttt{= 180}

<h3>Solution:</h3>

\texttt{5x}² \texttt{= 180}

<h3><u>Explanation:</u></h3>

<u></u>

Divide both sides by 5

\hookrightarrow{\mathtt{\frac{5x^2}{5}} = {\mathtt{\frac{180}{5}}

Simplify:

\hookrightarrow{\mathtt{x^2 = 36}

\hookrightarrow{\mathtt{For \: x^2 \: = f(a) \: the \: solutions \: are \: x = \sqrt{f(a)}} , \mathtt{- \sqrt{f(a)}}

\hookrightarrow{\mathtt{x = \sqrt{36}} , \mathtt{x = -\sqrt{36}}

Factor the number: 36 = 6²

\mathtt{= \sqrt{6^2}}

Apply radical rule: \mathtt{\sqrt[n]{a^n} \: = a}

\mathtt{\sqrt{6^2} = 6} \\\mathtt{= 6}

- \sqrt{36} = -6

\boxed{\fbox{\bf{x = 6 , x = -6}}}

Hope It Helps You...

xeze [42]2 years ago
4 0

Answer:

x = ± 6

Step-by-step explanation:

Hello!

<h3>Solve</h3>
  • 5x^2 = 180
  • x^2 = 180/5
  • x^2 = 36
  • \sqrt{x^2} = \sqrt{36}
  • x = \pm 6

The value of x is 6 or -6.

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