To have 2 real number solutions the discriminant b^2 - 4ac must be greater than zero.
so the condition for 2 real roots in this equation is:-
b^2 - 4*1*5 > 0
b^2 > 20
b > sqrt 20 ( positive root) Answer
Lets write as an equation:
x/4 + 18 = x
to get rid of fraction lets multiply the whole equation by 4:
x + 4*18 = 4x
x + 72 = 4x
3x = 72
x = 72/3
x = 24
that is the solution
1+5, 2+4, 3+3. 3 ways to make 6
