Create a system of equations
x + y = 123
5x + y = 343
I use substitution
y = 123 - x
5x + 123 - x = 343
4x + 123 = 343
4x = 220
x = 55
Plug in
x + y = 123
55 + y = 123
y = 68
Check
5x + y = 343
5(55) + 68 = 343
275 + 68 = 343
343 = 343
YOU DON"T HAVE TO YELL
512 PER STUDENT
BASICALLY,
CUBES NEEDED=CUBES PER STUDENT TIMES NUMBER OF STUDENTS
NUMBER OF STUDENTS=28+25=53
CUBES PER STUDENT=512
CUBES NEEDED=512 TIMES 53 EQUALS 27136 CUBES
SHE NEEDS 27136 CUBES FOR ALL HER STUDENTS
I hope this helps you
✔cos^2A+sin^2A=1
✔1-cos^2A=sin^2A
✔cos2A=cos^2A-sin^2A
✔sin2A=2.sinA.cosA
secA=1/cosA
tgA=sinA/cosA
sin^2A/1/cos^2A-sin^2A/cos^2A
sin^2A.cos^2A/cos2A
2.sin^2A.cos^2A/cos2A
sin2A.2.sin2A/cos2A
tg2A.2.sin2A
Answer:
y-4=-2(x+1)
Step-by-step explanation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(-4-4)/(3-(-1))
m=-8/(3+1)
m=-8/4
m=-2
y-4=-2(x-(-1))
y-4=-2(x+1)
