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Ilya [14]
2 years ago
10

Pls helppp...

Business
1 answer:
Aloiza [94]2 years ago
8 0

Answer:

32 700

Explanation:

that is the answer 32 700

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Part 1: What is the problem with the Manager asking you to adjust the bad debt loss until it meets the desired bonus?
geniusboy [140]

Part 1. The problem with the manager asking for an adjustment of the bad debt loss to meet the desired bonus is that it is <u>unethical</u>.

<h3>What is ethical accounting?</h3>

Ethical accounting follows the specific rules of the accounting profession and not the personal biases of management.

Accounting ethics deals with the following principles:

  • Integrity
  • Objectivity
  • Professionalism,
  • Confidentiality
  • Professional competence and due care.

Part 2. The amount that would be recorded as the bad debt expense is $10,560

<h3>Data and Calculations:</h3>

2% of $33,000 =       $660
5% of $14,000 =        $700

10% of $22,000 =  $2,200

25% of $12,000 =  $3,000

40% of $10,000 =  $4,000

Total                     $10,560

Part 3. The bad debt expense for the year would be $10,560 if there were no previous balance of the allowance for doubtful accounts.

Part 4. Since the required information is lacking, we can conclude that it is unethical behavior if the bad debt expense must be adjusted to meet the desired bonus target.

Learn more about ethical accounting at brainly.com/question/13396824

#SPJ1

6 0
2 years ago
As the business grows:
tamaranim1 [39]

Answer:

As the business grows: salaries and wages will go up as output increases

Explanation:

If a business tends to grow the salaries of the workers will go up and wages will increase too because now there s more output compared to when the business started and you will have to probably hire more workers or pay for overtime.

3 0
3 years ago
Read 2 more answers
If the marginal propensity to consume (MPC) is 0.8, and transfers increase by $100 billion, then GDP will: Please choose the cor
Talja [164]

Answer:

Increase by more than $500 billion.

Explanation:

Use the below formula to find the multiplier effect.

Multiplier = 1 / (1-MPC)

Multiplier = 1 / (1 - 0.8)

Multiplier = 1 / 0.2

Mulitiplier = 5

GDP increase by = 5 x 100

GDP increases by = $500

Since the multiplier is five and the increase in transfer by $100 that will have multiplier effect of $500. Thus option "a" is correct.

4 0
3 years ago
A dishwasher uses 700 watts each time it is run. the cycle takes one hour. it is run 150 times per year. how much energy does it
sashaice [31]
<span>To first solve this problem, we have to set up ratios based on the data given. First, we know that the dishwasher use rate is 700 watts/run. Next, we know 1 hr/run. Finally, we know there are 150 runs/year. To calculate how much energy per year, we arrange the ratios to give a final answer of watts/year. Doing this we get the following: 150 runs/year * 700 watts/run = 105,000 watts/year which is also equal to 105 kw/year. The ration of 1 hour per run does not make a difference in this question and is not needed for the final answer.</span>
3 0
3 years ago
A metal sphere of radius 15 cm has a net charge of 3.0 $ 10#8 C. (a) What is the electric field at the sphere’s surface? (b) If
denis-greek [22]

Answer:

E = 1.20 × 10^{4} N/C

V = 1800 V

x = 0.058 m

Explanation:

given data

radius = 15 cm

net charge = 3 × 10^{-8} C

electric potential decreased = 500 V

solution

we get here electric field at the sphere’s surface that is

electric field at the sphere’s surface E  =  \frac{q}{4\pi \epsilon _o R^2}   ............1

put here value

electric field at the sphere’s surface E  = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15^2}    

E = 1.20 × 10^{4} N/C

and

potential on surface of sphere is

V =  \frac{q}{4\pi \epsilon _o R} ................2

V = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15}  

V = 1800 V

and

now we get distance that is x

and we know here

ΔV = V(x) - V   ..............3

substitute here value

-500V = \frac{q}{4\pi \epsilon _o } \times (\frac{1}{R+x} - \frac{1}{R})

-500 V = {3\times 10^{-8}\times 8.99\times 10^9} \times (\frac{1}{0.15+x} - \frac{1}{0.15})

solve it we get x

x = 0.058 m

3 0
3 years ago
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