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AleksAgata [21]
2 years ago
11

the state transferred ownership of property to roger and pauline. which transfer document would the state agency use?

Business
1 answer:
elena55 [62]2 years ago
7 0

The state transferred ownership of property to Roger and Pauline, the transfer document that the state agency will use us a deed of assignment.

<h3>What is a deed of assignment?</h3>

It should be noted that the deed of assignment simply means an instrument that's used to illustrate that a transfer has taken place.

Any property transaction needs a deed of assignment because it serves as the primary record between the seller and the buyer proving that all negotiations, inquiries, and other required due diligence have been made, the purchase price has been paid, and all other prerequisites have been met.

In this case, the state transferred ownership of property to Roger and Pauline, the transfer document that the state agency will use us a deed of assignment.

Learn more about assignment on:

brainly.com/question/13858252

#SPJ1

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alexira [117]

Answer:

Jessica calls her colleagues informing them about her new bakery business.

Explanation:

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2 years ago
Amy and Lance are newlyweds. This is Lance's second marriage. Because of problems that occurred before his divorce (his ex-wife
yanalaym [24]

Answer:

c. Tenancy by the entirety

Explanation:

Based on the information provided within the question it can be said that in this scenario the best account recommendation would be a Tenancy by the entirety. This is an account in which each spouse in a marriage has an equal and undivided interest in the account and approval from both parties is needed to empty out the account.

8 0
3 years ago
During its first year of operations, Novak Corp. Had these transactions pertaining to its common stock. Jan. 10 Issued 26,000 sh
bonufazy [111]

The journal entries to record the common stock transactions under the two scenarios are as follows:

a) Assuming that the common stock has a par value of $4 per share:

Jan. 10 Debit Cash $104,000

Common Stock $104,000

July 1 Debit Cash $495,000

Common Stock $220,000

Additional Paid-in Capital $275,000

b) Assuming that the common stock is no-par with a stated value of $3 per share

Jan. 10 Cash $104,000 Common Stock $78,000 Additional Paid-in Capital $26,000

July 1 Cash $495,000 Common Stock $165,000 Additional Paid-in Capital $330,000

<h3>What is the difference between par value and stated value?</h3>

There is <u>no major difference</u> between the par value and the stated value of the common stock, except as follows.

While the stated value is assigned when there is no par value for accounting purposes, the par value is assigned when the shares are authorized for issuance.

The two function as the face value of the shares which can be compared to the market value to discover if there is additional paid-in capital or not.

<h3>Data and Calculations:</h3>

a) Jan. 10 Cash $104,000 Common Stock $104,000

July 1 Cash $495,000 Common Stock $220,000 Additional Paid-in Capital $275,000

b) Jan. 10 Cash $104,000 Common Stock $78,000 Additional Paid-in Capital $26,000

July 1 Cash $495,000 Common Stock $165,000 Additional Paid-in Capital $330,000

Learn more about recording stock issuance transactions at brainly.com/question/17201601

7 0
2 years ago
A company, which records its delivery trucks at the market price, has violated the following concept:
klio [65]

Yo Mf leave this page right now nobody cares abot your questions

4 0
3 years ago
A bottling operation has a mean fill level of 10.01 ounces with a standard deviation of 0.25 ounces. Random samples of 20 bottle
MAVERICK [17]

Answer:

The upper limit is 10.1

The lower limit is 9.91

Explanation:

Given that:

The mean fill level (μ) = 10.01 ounces,

Standard deviation (σ) = 0.25 ounces

Number of sample bottles (n) = 20

The limits of the sample mean = 92% = 0.92

α = 1 - 0.92 = 0.08

\frac{\alpha}{2}=0.04

The z value of 0.04 is the same as the z value of 0.46 (0.5 - 0.04). From the probability distribution table:

z_{\frac{\alpha}{2}}=z_{0.04} = 1.75

The margin of error (e) is given by:

e=z_{0.04}\frac{\sigma}{\sqrt{n} }=1.75*\frac{0.25}{\sqrt{20} }  =0.1

The upper limit = μ + e = 10.01 + 0.1= 10.1

The lower limit = 10.01 - 0.1 = 9.91

6 0
3 years ago
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