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gizmo_the_mogwai [7]

2 years ago

11

Alice gave Bob as many dollars as Bob had. Bob then gave Alice as many dollars Alice then had. At this point, each had 24 dollar

s. How much did Alice have at the beginning?
Please answer it step-by-step, and explained it very detailed. Thx.

1 answer:

valentina_108 [34]2 years ago

7 0

Answer:

x = y

Step-by-step explanation:

x = y

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(Will mark branliest please help!! :) Find the area of the figure.

jeka57 [31]

Answer:

Well, let's break it down.

Since calculating a triangle is like calculating a rectangle, then sawing it in half, we can correctly decide that the top and bottom right sections are both equal to twelve, adding up to 24. Now for the other two, we can use another quick trick; by instead of adding the equal right triangles, you can skip the division and multiplication by two, leaving us with a square area of 16. 24 + 16 is 40, and since we are working with millimeters instead of meters, the answer must be D

tl/dr: D

Hope this helps!

Step-by-step explanation:

3 0

3 years ago

What is the length of a short leg of a 30-60-90 triangle shown below?

Alekssandra [29.7K]

Answer:

5

Step-by-step explanation:

since 30-60-90 triangles are special right triangles, we know that if the short leg=x, the long leg= xsqrt(3). so the short leg= 5 sqrt(3) /(sqrt(3) = 5

7 0

2 years ago

Classify the following numbers as Natural, Whole number, irrational, non real, rational

sineoko [7]

Answer:

sqroot(111) is irrational.

Step-by-step explanation:

Natural are 1, 2, 3, 4...

Whole are 0, 1, 2, 3...

Irrational are decimals that don't end or repeat. Sqroot(111) is 10.535653752...

Nonreal have an i, the imaginary number.

Rational are fractions (or can be written as a fraction) or decimals that end or repeat.

6 0

3 years ago

Based on your observations, what conclusion can you draw about the lengths of AB DB AE EC

Deffense [45]

Answer:

The ratio of AD to DB is equal to the ratio of AE to EC. In other words, the pairs of lengths are proportional.

Step-by-step explanation:

Sample answer from plato

4 0

3 years ago

TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streamin

choli [55]

Answer:

a) The 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

b) $n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51$

And rounded up we have that n=1831

Step-by-step explanation:

Data given and notation

n=2341 represent the random sample taken

X represent the people that they have watched digitally streamed TV programming on some type of device

$\hat p=0.55$ estimated proportion of people that they have watched digitally streamed TV programming on some type of device

$\alpha=0.01$ represent the significance level

Confidence =0.99 or 99%

z would represent the statistic for the confidence interval

p= population proportion of people that they have watched digitally streamed TV programming on some type of device

The population proportion present the following distribution:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}}$

Part a) Confidence interval

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.55 - 2.58 \sqrt{\frac{0.55(1-0.55)}{2341}}=0.523$

$0.55 + 2.58 \sqrt{\frac{0.55(1-0.55)}{2341}}=0.577$

And the 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

Part b) What sample size would be required for the width of a 99% CI to be at most 0.03 irrespective of the value of p??

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51$

And rounded up we have that n=1831

8 0

4 years ago