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3 years ago

A relation must have exactly one output for every input. T/F?

2 answers:

5 0

False. A relation can have multiple outputs for any given input.

Note: if you change "relation" to "function", then the statement would be true.

mart [117]3 years ago

4 0

Answer:

false

Step-by-step explanation:

((this for those that come earlier when i posted this lol bc i know im very late to answer))

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Factor completely:<br> x^2-x^2-3.5(x+y)

kkurt [141]

Answer:

− 3.5 ( x + y )

Hope this helps

Step-by-step explanation:

3 0

2 years ago

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Draw a model showing 15 divided by 3

kykrilka [37]

Here is you're answer:

In order to solve this equation you must first solve the equation then make a model.

$15 \div 3 = 5$
$=5$

Draw three circles then divide 15 between the 3 circles to equal 5.

Therefore you're answer is "5."

Hope this helps!

6 0

3 years ago

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Tanya [424]

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3 years ago

Write the exponential function that represents the same relationship for each table! please help!!

Taya2010 [7]

5. Y=1/2x+12
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6 0

2 years ago

Dennis is cutting construction paper into rectangles for a project he needs to cut one rectangle that is 12 inches times 15 1/4

Nataly_w [17]

Answer:

Dennis need 288.91 square inches of construction paper for his project.

Step-by-step explanation:

Dennis is cutting construction paper into rectangles for a project.

He needs to cut one rectangle that is 12 inches times 15 1/4 inches

First convert the mixed fraction to improper fraction

$15\frac{1}{4} = \frac{(15\times4) + 1}{4} = \frac{61}{4}$

So the area of 1st rectangle is

$A_1 = 12\times \frac{61}{4} = 183 \: in^{2}$

He needs to cut another rectangle that is 10 1/3"" x 10 1/4""

The symbol " means inches

First convert the mixed fraction to improper fraction

$10\frac{1}{3} = \frac{(10\times3) + 1}{3} = \frac{31}{3}$

$10\frac{1}{4} = \frac{(10\times4) + 1}{4} = \frac{41}{4}$

So the area of 2nd rectangle is

$A_2 = \frac{31}{3}\times \frac{41}{4} = 105.91 \: in^{2}$

The total construction paper needed for this project is

$A = A_1 + A_2\\\\A = 183 + 105.91\\\\A = 288.91 \: in^{2}$

Therefore, Dennis need 288.91 square inches of construction paper for his project.

6 0

3 years ago