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Nimfa-mama [501]
4 years ago
8

A classroom globe has a diameter of 12 inches. What is the volume of the globe? Use 3.14 for pi. Round your answer to the neares

t hundredth. 
904.32 in3 

2144.66 in3

7238.23 in3

9202.77 in3
Mathematics
2 answers:
Alecsey [184]4 years ago
6 0
<span>V=<span>\frac{4}{3}  \pi r^{3}

r=12/2=6
pi=3.14
</span></span>
V=\frac{4}{3}(3.14)*(6)^{3}

V=\frac{4}{3}(3.14)*216=904.32 in^{3}

The answer is 904.32 in^{3}. Sorry. I used the wrong formula. ^^;
Vladimir [108]4 years ago
6 0
The answer would be 904.32
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A rectangular football field is 64 meters wide and 100 maters long. A player runs from one corner of the field in a diagonal lin
Dimas [21]

Answer:

119 or 118.726577

Step-by-step explanation:

We should use the Pythagorean Theorem to solve this problem.

a^2+ b^2=c^2

64^2+100^2=c^2

4096+10000=14096

c^2=14096

c=\sqrt{14096}14096

And the root of 14096 is 118.726577.

So the Answer is About 119 meters, or 118.726577

hope this helps!

3 0
3 years ago
What’s the answer I don’t understand it or know it.
fredd [130]

Answer:

I tried solving it and didn't get same exact numbers but I got 8.67 million people so it might be answer choice B.

7 0
3 years ago
Jose equation is -4(x+2) = 8x+16 says to jill “I can solve for the variable in this equation in at least 4 different ways
erastovalidia [21]

Answer:

that is step 1 and step 2 and step3

step 4

Let's solve your equation step-by-step.

−4(x+2)=8x+16

Step 1: Simplify both sides of the equation.

−4(x+2)=8x+16

(−4)(x)+(−4)(2)=8x+16(Distribute)

−4x+−8=8x+16

−4x−8=8x+16

Step 2: Subtract 8x from both sides.

−4x−8−8x=8x+16−8x

−12x−8=16

Step 3: Add 8 to both sides.

−12x−8+8=16+8

−12x=24

Step 4: Divide both sides by -12.

−12x

−12

=

24

−12

x=−2

Answer:

x=−2

6 0
3 years ago
An English professor assigns letter grades on a test according to the following scheme. A: Top 9% of scores B: Scores below the
sergeinik [125]

Answer:

The minimum score required for an A grade is 83.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 72.3 and a standard deviation of 8.

This means that \mu = 72.3, \sigma = 8

Find the minimum score required for an A grade.

This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.

Z = \frac{X - \mu}{\sigma}

1.34 = \frac{X - 72.3}{8}

X - 72.3 = 1.34*8

X = 83

The minimum score required for an A grade is 83.

5 0
3 years ago
"Determine the intercepts of the line"
Inessa05 [86]
X=-1/3 y+4

y=-3x+12

hope this helps!
7 0
3 years ago
Read 2 more answers
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