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fredd [130]
3 years ago
14

Jose equation is -4(x+2) = 8x+16 says to jill “I can solve for the variable in this equation in at least 4 different ways

Mathematics
1 answer:
erastovalidia [21]3 years ago
6 0

Answer:

that is step 1 and step 2 and step3

step 4

Let's solve your equation step-by-step.

−4(x+2)=8x+16

Step 1: Simplify both sides of the equation.

−4(x+2)=8x+16

(−4)(x)+(−4)(2)=8x+16(Distribute)

−4x+−8=8x+16

−4x−8=8x+16

Step 2: Subtract 8x from both sides.

−4x−8−8x=8x+16−8x

−12x−8=16

Step 3: Add 8 to both sides.

−12x−8+8=16+8

−12x=24

Step 4: Divide both sides by -12.

−12x

−12

=

24

−12

x=−2

Answer:

x=−2

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15*9/2 =67.5

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A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f
mestny [16]

Answer:

The value is W= 2640 \  ft \cdot lb

Step-by-step explanation:

From the question we are told that

The weight of the bucket is F =  5 lb

The depth of the well is x_1 =  60 \ ft

The weight of the water is W_w  =  42 lb

The rate at which the bucket with water is pulled is v  = 1.5 \  ft/s

The rate of the leak is r = 0.15 lb/s

Generally the workdone is mathematically represented as

W =  \int\limits^{x_1}_{x_o} {G(x)} \, dx]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

G(x) =  F  +  (W_w- Ix)

Here I is the rate of water loss in lb/ft mathematically represented as

I  = \frac{r}{v}

=> I  = \frac{0.15 }{1.5 }

=> I  = 0.1

So

G(x) =  5  +  (42- 0.1x)

=> G(x) =  47- 0.1x)

So

W =  \int\limits^{60}_{0} {47- 0.1x} \, dx]

=> W =  [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.

=> W= [47(60) - 0.05(60)^2]

=> W= 2640 \  ft \cdot lb

7 0
3 years ago
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