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2 years ago

A) Copy a segment using the construction tool. Insert a screenshot of the construction here.

1 answer:

8 0

We need to understand circles and colinear points in order to use the building tool to create a circle.

<h3 /><h3>What exactly is a circle?</h3>

It is a point locus drawn equidistant from the center. The radius of the circle is the distance from the center to the circumference.

Draw arcs such that they all bisect one another at a point, which will be the center of the circle, starting with three non-colinear points (points A, B, and C).

Additionally, the radius will match the distance between the arcs' centers and their correspondingly drawn arcs.

Hence we need to understand circles and colinear points in order to use the building tool to create a circle.

To learn more about the circle, refer to the link: brainly.com/question/11833983.

#SPJ1

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Paul went on a bike ride of 30 miles. He realized that if he had gone 8 mph faster, he would have arrived 12 hours sooner. How f

lara [203]

Answer: He actually rode 2 miles per hour on his trip

Step-by-step explanation: Maybe unconventional, but express the time it took, then figure the speed.

Time = distance /speed t will represent time, s is the speed: t = 30/s Use the rime it would have taken at the higher speed to create an equation:

t-12 = 30/s+8 replace the y with the 30/s

30/s -12 = 30/s+8

(s)(30/s -12 ) = (s)(30/s+8 ) Cross multiply to cancel denominators

(s-8)(30 -12s) = (s-8)(30s/s+8 ) ==> 30s +240 -12s² -96s =30s Simplify:

(-1)(-12s² -96s +240 ) =0 ==> 12s² +96s -240 divide all by 12

s² + 8s -20 = 0 Factor and solve for s

(s +10)(s -2) =0 s-2=0 S= 2

Proof:

30/2 = 15 hours for original trip at 2mph,

increase speed by 8mph 2 + 8 = 10mph

30 miles at 10mph takes 3 hours; that is 12 hours less than his actual trip.

(Brainilest, please :-)

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3 years ago

I WILL AWARD BRAINLIEST!! PLEASE HELP!!! The figure below shows the movement of a pedestrian from point B to point E. Using the

jeyben [28]

Answer:

Step-by-step explanation:

A) What is the speed of the pedestrian BC, CD, and DE?

Speed from B to C = distance/time = (40 - 20) / 4 = 20/4

= 5 km/h

Speed from C to D = distance/time = 0 / 2

= 0 km/h

Speed from D to E = distance/time = (20 - 0) / (10 - 6) = 20/4

= 5 km/h

B) After what time since the stop did he arrive at point E?

Since the stop at D, he arrived at E after (10 - 6) = 4 h

C) Write the formulas for function d(t) for sections BC, CD, and DE

For BC, d = 40 when t = 0 and d = 20 when t = 4

So d(t) = 40 - 5t

For CD, d = 20 when t = 4 and t = 6

So d(t) = 20

For DE, d = 20 when t = 6 and d = 0 when t = 10

So d(t) = 5 * (10 - t) or d(t) = 50 - 5t

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3 years ago

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B I have done this before

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1 mile is equal to 5280 feet

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Pachacha [2.7K]

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