Answer:
90° is correct answer. :)
3a. Megan's car has more gas
3b. 2/3=66.666% and 3/5= 60% so 6 2/3 gallons
5. 108.09-15.45= 92.64
Answer:
it should still be 166
Step-by-step explanation:
because bfa should be the same as bda
that's what i learnt about this
but i did this a long time ago so im about 70 percent sure that this is correct
Answer:
The probability of falling into a type I error, when testing a hypothesis test, consists of:
Probability of rejecting the null hypothesis when, in reality, this hypothesis is true.
Probability of rejecting the null hypothesis when, in reality, this hypothesis is true, is:
Probability of Affirm that Chemistry exam will NOT cover only chapters four and five, since the Chemistry exam will cover only chapters four and five.
That is, alpha is the probability that Carmin decides to study additional chapters, unnecessarily.
Step-by-step explanation:
Answer: 15e^5x
Step - by - step
y=3e^5x - 2
By the sum rule, the derivative of 3e^5x - 2 with respect to x is d/dx [ 3e^5x ] + d/dx [-2].
d/dx [ 3e^5x ] + d/dx [ -2 ]
Evalute d/dx [ 3e^5x ]
Since 3 is constant with respect to x , the derivative of 3e^5x with respect to x is
3 d/dx [ e^5x ].
3 d/dx [ e^5x ] + d/dx [ -2 ]
Differentiate using the chain rule, which states that d/dx [ f(g(x))] is f' (g(x)) g' (x) where f(x) = e^x and g(x) = 5x.
To apply the Chain Rule, set u as 5x.
3 ( d/du [ e^u] d/dx [5x] ) + d/dx [ -2]
Differentiate using the Exponential rule which states that d/du [ a^u ] is a^u ln(a) where a=e.
3( e^u d/dx[5x] ) + d/dx [ -2 ]
Replace
3(e^5x d/dx [5x] ) + d/dx [ -2 ]
3(e^5x( 5 d/dx [x] )) + d/dx [ -2 ]
Diffentiate using the Power Rule which states that d/dx [x^n] is nx^n-1 where n=1.
3(e^5x(5*1)) + d/dx [-2]
3 ( e^5x * 5 ) + d/dx [-2]
Multiply 5 by 3
15e^5x + d/dx [-2]
Since -2 is constant with respect to x, the derivative of -2 with respect to x is 0.
15e^5x + 0
15e^5x
