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2 years ago

If x+4 is a factor of x^2-ax-12a and a is a constant, what is the value of a?

SAT

1 answer:

Artyom0805 [142]2 years ago

8 0

Answer:

$x^{2} -ax-12a=(x+4)(x-4-a)-8a+16\\x+4 is a factor of x^2-ax-12a\\-8a+16=0\\a=2$

Explanation:

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Answer:

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