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faltersainse [42]
2 years ago
14

If x+4 is a factor of x^2-ax-12a and a is a constant, what is the value of a?

SAT
1 answer:
Artyom0805 [142]2 years ago
8 0

Answer:

x^{2} -ax-12a=(x+4)(x-4-a)-8a+16\\x+4 is a factor of x^2-ax-12a\\-8a+16=0\\a=2

Explanation:

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1 year ago
If f(x)=(x+3)³+4<br> let g(x)=f(x+1)-2<br> find when g(x)=12
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Answer:

Explanation:

g(x) = f(x + 1) - 2

g(x) = (x + 1 + 3)^3 -2

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Now what are we supposed to do with this? I'm guessing we are to find what value of x will make g(x) = 12. If I'm wrong, leave a note in the form of a comment.

g(x) = 12

(x + 4)^3 - 2 = 12                 Add 2 to both sides.

(x + 4)^3 = 14                      Take the cube root of both sides.

x + 4 = cubrt(14)

x + 4 = 2.4101                      Subtract 4

x = 2.4101 - 4

x = -1.5899

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