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faltersainse [42]
2 years ago
14

If x+4 is a factor of x^2-ax-12a and a is a constant, what is the value of a?

SAT
1 answer:
Artyom0805 [142]2 years ago
8 0

Answer:

x^{2} -ax-12a=(x+4)(x-4-a)-8a+16\\x+4 is a factor of x^2-ax-12a\\-8a+16=0\\a=2

Explanation:

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