Question

The Maxair amusement park ride consists of a circular ring that holds 50 riders. Suppose that the center of the ride is at the origin and that one of the riders on the circular ring is at (16, 15.1). If one unit on the coordinate plane equals 1 foot, give an approximation of the circumference of the ride to the nearest foot.

Answer 1

The approximation of the circumference of the ride is 138 feet to the nearest foot

How to determine the circumference?

The given parameters are:

• Center (a,b) = (0,0) i.e. the origin
• A circular ring, (x,y) = (16,15.1)

The radius is calculated using:

$r = \sqrt{(x - a)^2 + (y -b)^2}$

So, we have:

$r = \sqrt{(16 - 0)^2 + (15.1 -0)^2}$

Evaluate

r = √484.01

Evaluate the square root

r = 22.0

The circumference is calculated using

C = 2πr

So, we have:

C = 2π * 22.0

Evaluate

C = 138

Hence, the approximation of the circumference of the ride to the nearest foot is 138 feet

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