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Serga [27]
2 years ago
10

Solve each of the following quadratic equations 3x=0.5x^2 0=5x^2-2x+6

Mathematics
1 answer:
UNO [17]2 years ago
6 0

<u>Question 1</u>

<u />3x=0.5x^{2}\\\\6x=x^{2} \\ \\ x^{2}-6x=0 \\ \\ x(x-6)=0 \\ \\ \boxed{x=0, 6}

<u>Question 2</u>

<u />0=5x^{2}-2x+6 \\ \\ x=\frac{2 \pm \sqrt{(-2)^{2}-4(5)(6)}}{2} \\ \\ x=\frac{2 \pm \sqrt{-116}}{10} \\ \\ x=\frac{2 \pm 2i\sqrt{29}}{10} \\ \\ \boxed{x=\frac{1 \pm i\sqrt{29}}{5}}

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Converting to base 10 can be done easily by writing a sort of digit expansion. In base 6, this number literally means

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