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Leto [7]
3 years ago
10

Suppose tan(b) = –2, and the terminal side of b is located in quadrant II. What is cot(b)?

Mathematics
1 answer:
Harman [31]3 years ago
4 0

Answer:

cot(b)= -2

Step-by-step explanation:

on edge

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1. Find the equation of a line passing through the points (1,-2) and (-3,10).​
liraira [26]

Answer:

Step-by-step explanation:

(1 , -2)   x₁ =1 & y₁ = -2

(-3,10)  x₂= -3 & y₂ = 10

First we need to find the slope.

\boxed{Slope = $\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$}\boxed{Slope=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}

          =\dfrac{10-[-2]}{-3-1}\\\\\\=\dfrac{10+2}{-4}\\\\\\=\dfrac{12}{-4}\\\\\\= - 3

m = -3

Equation of the line: y = mx + b

y = -3x + b

To find the value of b, take one of the point and substitue in the above equaiton.

(1 , -2)

-2 = -3*1 + b

-2 = -3 + b

-2 + 3 = b

b = 1

Equation of the line:

y = -3x + 1

4 0
3 years ago
Math help!!! Who know the answers???
NeTakaya

Answer:

original: -5, 1

Final: 2, 1

7 0
3 years ago
Ethan was given a gift card for a coffee shop. Each morning, Ethan uses the card to buy one cup of coffee. Each cup of coffee co
rjkz [21]

Answer:

$69.99 or $50.08

Step-by-step explanation:

2 for 1 by dividing by 100: 80/100 =0.8 mulitply price by decimal rate

4 0
3 years ago
HELP PLZ I NEED IT
vladimir2022 [97]

Answer:

false

Step-by-step explanation:

18 is not = to 21

3 0
3 years ago
n engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that
BartSMP [9]

Answer:

<em>The calculated t- value =  1.11 > 2.89 at 0.025 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The engineer designed the valve such that it would produce a mean pressure is not equal to  5.4</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the Population (μ) = 5.4</em>

<em>Given sample size 'n' = 9</em>

<em>Mean of the sample (x⁻) = 5.7</em>

<em>Standard deviation of the sample (s) = 0.81</em>

<u><em>Step(ii):-</em></u>

<em>Null Hypothesis: H₀:</em>  The engineer designed the valve such that it would produce a mean pressure of 5.4

H₀: μ = 5.4

<em>Alternative Hypothesis : H₁:</em>  μ ≠ 5.4

Level of significance = 0.025

Test statistic

            t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

           t = \frac{5.7 -5.4}{\frac{0.81}{\sqrt{9} } }

         t = 1.11

<em>Degrees of freedom </em>

<em>ν = n-1 = 9-1 =8</em>

t₀.₀₁₅ , ₈  = 2.89

<em>The calculated t- value =  1.11 > 2.89 at 0.025 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The engineer designed the valve such that it would produce a mean pressure is not equal to  5.4</em>

<em></em>

<em />

7 0
3 years ago
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