Q1. The answer is To solve, you must divide both sides by 6
The equation is: 6d = 12
<span>Multiplication is the inverse operation: TRUE - 6d = 12 d = 12/6
Checking the solution involves multiplication: TRUE - 6 * 2 = 12
The equation represents the number that gives twelve when multiplied by 6: TRUE d is </span>the number that gives twelve when multiplied by 6<span>
To solve, you must divide both sides by 6: false
Q2. The answer is 18
</span><span>
x - the number of students
The students were divided equally among 3 chaperones: 3 chaperones per x
Each chaperone supervised 6 students: 1 chaperone per 6 students
3 : x = 1 : 6
x = 3 * 6 : 1
x = 18
Q3. The answer is </span><span>t is greater than or equal to five.
</span>
It will take Harlon at least five years to complete his college degree. The key word is at least. This means that it can include number 5 as well. He may need 5 years, 6 years, 7 years,... Hence, t is greater than or equal to five.
Q4. The answer is <span>1.2
</span>
<span>p over zero point three + 2 = 6
p/0.3 + 2 = 6
multiply both sides by 0.03
p + 2 * 0.3 = 6 * 0.3
p + 0.6 = 1.8
p = 1.8 - 0.6
p = 1.2
Q5. The answer is 2.
</span><span>16w = 32
Divide both sides by 16
16w/16 = 32/16
w = 2</span>
That would be C....(1 x 10^-1) + (6 x 10^-2) + (9 x 10^-3)
Answer:
a=8.06
A=29.74
B=60.26
Step-by-step explanation:
This is a right angled triangle and Pythagoras theorem is to be obeyed.
To get c, we follow the Pythagoras rule that says
Hyp² = Opp² + Adj²
c= Hypotenuse
c²= a² + b²
c² = 4² + 7²
c² = 65
c = √65 = 8.06
For angle A,
the opposing side to the angle = a = 4
The adjacent side to the angle = b = 7
Following trigonometry rule.
Tan A = opp/adj
Tan A = 4/7
A = Tan–¹(4/7)
A = 29.74°
For angle B,
Opposing side = 7
Adjacent side = 4
Tan B = 7/4
B = Tan-¹(7/4)
B = 60.26°
<span>Using place value to exchange equal amounts when renaming a number is called : Regroup
Simple example for a group is when you try to add up :
86 + 25
86 has 8 group of tens and 6 groups of one
25 has 2 groups of tens and 5 groups of one
after adding that up , now the number has 11 group of tens and 1 group of one, the result of that equation would be : 110</span>
Answer:
Step-by-step explanation:
What this question is asking of you is what is the greatest common divisor of 12 and 15. Or, what is the biggest number that divides both 12 and 15.
in order to find this we have to split each number into it's prime components.
for 12 they are 2,2 and 3 (
2
⋅
2
⋅
3
=
12
)
and for 15 they are 3 and 5 (
3
⋅
5
=
15
)
Out of those two groups (2,2,3) and (3,5) the only thing in common is 3, so 3 is the greatest common divisor. That tells us that the greatest number of groups that can exist and have the same number of girls and the same number of boys for each group is 3.
Now to find out how many girls and boys there are going to be in each group we divide the totals by 3, so:
12
3
=
4
girls per group, and
15
3
=
5
boys per group.
(just as a thought exercise, if there were 16 boys, the divisors would have been (2,2,3) and (2,2,2,2), leaving us with 4 groups [
2
⋅
2
] of 3 girls [12/4] and 4 boys [16/4] )
