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jeka94
2 years ago
7

Please, I need help with this math question.

Mathematics
1 answer:
kondaur [170]2 years ago
8 0

Step-by-step explanation:

Indeed the brainliest is t

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3 years ago
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Leya [2.2K]

Answer:

Given the equation: 3x^2+14x+16=0

The general equation of quadratic formula for ax^2+bx+c=0 where a, b and c are constant;

then, the solution for this equation  is given by;

&#10;x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}              ......[1]

From the equation, 3x^2+14x+16=0 we have

a =2, b=14 and c=16

Substitute these values in [1] to solve for x;

&#10;x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-14\pm\sqrt{(14)^2-4(3)(16)}}{2(3)}              

or

x=\frac{-14\pm\sqrt{196-192}}{6} =\frac{-14\pm\sqrt{4}}{6}

Simplify:

x=\frac{-14\pm\sqrt{4}}{6} =\frac{-14\pm 2}{6}

then,

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6 0
3 years ago
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