First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
Here Is Your Answer Of Your Question and Please Subscribe To Auroza Gaming
We find the average by adding up all the students and dividing them by the number of classes she has. 19 + 13 + 19 + 9 + 14 + 15 is 89, and that divided by 6 is approximately 14.8, rounded to the nearest tenth.
---
Hope this helps!
