In a simple machine, how much work is done when an input of 10 n acts over a distance of 5 m?

What are rational and irrational numbers ?

lbvjy [14]

Rational: Any number that can be expressed as a fraction (or a ratio.)
Irrational: Not rational, any number that can't be written down as a fraction. Some examples include $\pi (3.1415926...)$ , $\sqrt{2}$ , and so on.

6 0

3 years ago

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4. How many real-number solutions does the equation have?

erma4kov [3.2K]

2 solutions. This is because the parabola will cross the x axis twice. We know this because -5 means the vertex will be 5 units below the x axis. and the parabola opens upwards because the first coefficient is positive. Hope this helped :)

5 0

4 years ago

What is 4 1/4 divided 4 1/2

Ainat [17]

If you can use a calculator, enter (4/1/4)/(4/1/2) and you will get 1/2

8 0

3 years ago

Plot the x-intercept(s), y-intercept, vertex, and axis of symmetry for the function below.

telo118 [61]

g(x) = x^2 + 4x + 3

y-intercept: let x=0. Then y=3. y-intercept is (0,3).

roots: set g(x) = 0 and solve for x. x=-1 and x=-3.

-4
axis of symmetry: find x = -b / (2a), which here is x = ----- = -2
2

6 0

3 years ago

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2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago