Question

Find angle p to the nearest degree in right triangle MNP for M(3,6), N(3, -8), and P (-5, -8).

Answer 1

Answer: $60^{\circ}$

Step-by-step explanation:

Note that NP = 8 and that MN = 14.

So,

$\tan P=\frac{14}{8}\\\\P=\tan^{-1} \left(\frac{14}{8} \right) \approx \boxed{60^{\circ}}$