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Romashka [77]
3 years ago
15

If x= −5, which equation is true?

Mathematics
1 answer:
saveliy_v [14]3 years ago
5 0
The answer is A] 2x -4 = -14

2(-5) -4 = -14
-10 -4 = -14
-14 = -14
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Pls help I’m confused
Misha Larkins [42]

Answer:

C or D but im pretty sure its C

Step-by-step explanation:

7 0
3 years ago
The given line passes through the points (-2,-4) and (2,2) What is the equation, in point-slope form, of the line that is parall
Morgarella [4.7K]

Answer:

(y-1)=\frac{3}{2}(x+3)


Step-by-step explanation:

The point slope form of a line is (y-y_1)=m(x-x_1) where x_1=-3\\y_1=1. We write  

(y-1)=m(x--3)\\(y-1)=m(x+3)


Since the line is parallel to the line shown it will have the same slope. To find m, count the slope from each marked point on the graph. Count the rise then the run and create a fraction rise/run. The slope is 6/4 which simplifies to 3/2. Now substitute it for m.

(y-1)=\frac{3}{2}(x+3)




3 0
3 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2 + 2xy − y2 + x = 20, (3
marin [14]
\bf x^2+2x6-y^2+x=20\impliedby taking\ \cfrac{dy}{dx}\textit{ to both sides}
\\\\\\ 2x+2\left( y+x\frac{dy}{dx}\right)-2y\frac{dy}{dx}=0\impliedby \textit{common factor 2}
\\\\\\
2\left[  x+\left( y+x\frac{dy}{dx}\right)-y\frac{dy}{dx}\right]=0
\\\\\\ x+y+x\frac{dy}{dx}-y\frac{dy}{dx}=0\impliedby \textit{common factor }\frac{dy}{dx}
\\\\\\
\cfrac{dy}{dx}(x-y)=-x-y\implies \cfrac{dy}{dx}=\cfrac{-x-y}{x-y}\qquad 
\begin{cases}
x=3\\
y=4
\end{cases}\ then
\\\\


\bf \cfrac{dy}{dx}=\cfrac{-3-4}{3-4}\implies \cfrac{dy}{dx}=7\\\\
-----------------------------\\\\
\textit{tangent equation at }\begin{cases}
x=3\\
y=4\\
m=7
\end{cases}
\\\\\\
y-4=7(x-3)\implies y=7x-21+4\implies y=7x-17
6 0
3 years ago
2x + y = 5<br> 4x + 2y = 0<br> Elimination
nordsb [41]
There is no solution
5 0
3 years ago
2 intersecting lines are shown. A line with point T, R, W intersects a line with points S, R, V at point R. Clockwise, from the
kolezko [41]

Answer:

Step-by-step explanation:

a) sum of angle on the straight line TRW is 180.

Given <TRS = 2x+10

<SRW = x-10

<TRS+<SRW = 180

2x+10+x-10 = 180

3x = 180

x = 180/3

x = 60°

<TRV = 180°-(2x+10)

Substitute x = 60° into the expression

<TRV = 180-(2(60)+10)

<TRV = 180-(120+10)

<TRV = 180-130

<TRV = 50°

2) From the diagram attached <MHJ= <LHK (oppositely directed angle)

Given

<MHJ= x+15

<LHK = 2x-20

Substitute the given data into the formula to get x

x+15= 2x-20

x-2x = -15-20

-x = -35

x = 35°

Next is to get the measure of <MHJ

<MHJ = x+15

<MHJ = 35+15

<MHJ = 50°

8 0
3 years ago
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