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SVETLANKA909090 [29]
2 years ago
12

Consider functions fand g.

Mathematics
1 answer:
Sauron [17]2 years ago
6 0

The value of (gof)(4) is 9 if the function f(x) is f(x) = -x³, and function g(x) is g(x) = |1/8x-1| option (B) is correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

f(x) = -x³

\rm g(x) =  |\dfrac{1}{8}x-1|

Plug x = 4 in the f(x)

f(4) = -4³ = -64

Plug the above value in the g(x)

\rm g(x) =  |\dfrac{1}{8}(-64)-1|

g(f(4)) = |-8-1| = |-9| = 9

Thus, the value of (gof)(4) is 9 if the function f(x) is f(x) = -x³, and function g(x) is g(x) = |1/8x-1| option (B) is correct.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

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3 years ago
What is the simplified value of the exponential expression 16^1/4?
erik [133]
<h2>Answer</h2>

2

<h2>Explanation</h2>

First, we are going to use the law of fractional exponents: a^{\frac{1}{n} =\sqrt[n]{a}

We can infer form our expression that a=16 and n=4, so let's replace the values:

a^{\frac{1}{n} =\sqrt[n]{a}

16^{\frac{1}{4} }=\sqrt[4]{16}

Notice that we can also decompose 16 into prime factors to get 16=2^4, so we can rewrite our expression as follows:

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