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Aloiza [94]
2 years ago
14

Write the equation of the trigonometric graph.

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
6 0

Answer:

started off from maximum, so f(x) = acos(bx)

max(f(x))=a=4

f(x)=4cos(bx)

the period is T = 2π

b=2π/T=2π/2π

b=1

f(x)=4cos(x)

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Convert the binary number 10101 to its base 10 equivalent.<br><br> 12<br> 21<br> 22<br> 31
Angelina_Jolie [31]

10101₂ = 1×2⁴ + 0×2³ + 1×2² + 0×2¹ + 1×2⁰

10101₂ = 16 + 0 + 4 + 0 + 1

10101₂ = 21

7 0
3 years ago
Read 2 more answers
Can someone help please? this is due soon. ill give brainliest
Iteru [2.4K]
Not sure but I think it’s B
4 0
3 years ago
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Please help and explain questions 20-22
zmey [24]
Hello!

The formula for circumference is 2\pi r and the formula for area of a circle is \pi r^{2}. Armed with these formulas, we can begin to find the circumferences and areas of the circles.

20. 
C = 2 \pi r
C = 2 \pi (6.5)
C = 13 \pi
C = 13(3.14)
C = 40.8

A = \pi r^{2}
A = \pi (6.5)^{2}
A = \pi (42.25)
A = 132.7

The circumference of the circle is 40.8 in and the area of the circle is 132.7 in².

21.
[Since we are given the diameter for this problem, to find the circumference, we no longer need to multiply the radius by 2 as in 2 \pi r because the diameter is the radius × 2. For \pi r^{2} we do need to divide the diameter by 2.]

C = 15.7 \pi
C = 49.3

A = \pi r^{2}
A = \pi (7.85)^{2}
A = 61.62 \pi
A = 193.5

The circumference of the circle is 49.3 in and the area of the circle is 193.5 in².

And that is all there is to it. I hope this helps you! (:
6 0
3 years ago
Which of these strategies would eliminate a variable in the system of equations?
Fofino [41]

Answer:

yes because a is the answer

Step-by-step explanation:

6 0
4 years ago
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a tire on a car rotates at 500rpm when the car is traveling at 50 km/h what is the circumference of the tire in meters
Nady [450]

50 km/h  = 50,000m / hr

= 50,000 / 60 = 833.333 m / minute

The tire rotates 500 times for this period

So the circumference of the tire = 833.333 / 500 m

= 1.67 m  to the nearest hundredth

=

5 0
3 years ago
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