On which triangle can the law of cosines be used to find the length of an unknown side? law of cosines: a2 = b2 + c2 – 2bccos(a)

2 answers:

7 0

A²=b²+c²-2bc Cos (a)
In this case , we can find the length of side a using the above cosine law.
If you are given the values of side b , c and angle a, then it is easy to calculate the length of side a.
To find side b,
b²=a²+c²-2ac Cos(b)
To find side c,
c²=b²+c²-2bc Cos (c)
Just the given values in the formula and get the length of the missing side. You can also find the missing angle using these formulas.

I hope this will help you.

lapo4ka [179]3 years ago

3 0

Answer:

It's B on edge

Step-by-step explanation:

I got it right

Also, to everyone who is mad at the first person who answered this, they probably don't have edge and the person who asked the question didn't give a picture. They did their best

You might be interested in

trasher [3.6K]

$\displaystyle\bf\\Explanations:\\\\The~similarity~ratio~of~two~similar~cones=k\\\\k=is~the~ratio~between~2~corresponding~lengths\\\\k=\frac{R_1}{R_2}=\frac{h_1}{h_2}\\\\The~ratio~between~2~corresponding~areas~of~similar~cones=k^2\\\\\frac{Area~1}{Area~2}=k^2\\\\The~ratio~between~the~volumes~of~the~2~similar~cones=k^3\\\\\frac{Volume~1}{Volume~2}=k^3$

$\displaystyle\bf\\Solving:\\\\Volume1=108~m^3\\\\Volume2=4m^3\\\\k^3=\frac{108}{4}\\\\k^3=27~~\Big|\sqrt{~}\\\\k=\sqrt[\b3]{27}\\\\k=3\\\\Area1=54~m^2\\\\\frac{Area~1}{Area~2}=k^2\\\\\frac{54}{Area~2}=3^2\\\\\frac{54}{Area~2}=9\\\\Area2=\frac{54}{9}\\\\\boxed{\bf Area2=6 m^2}$

4 0

3 years ago

And I also need help in this one.

Dvinal [7]

Hey bestie I’m pretty sure it’s 1:3

5 0

3 years ago

Benito runs 1/10 of a mile each day. Which shows how to find the number of days it will take for Benito to run 3/5 of a mile?

n200080 [17]

D is most likely right. Basically, I would turn them into decimals and divide using a graphing calculator.

4 0

3 years ago

One number is 8 a first number . A third number is 100 more than the first number . If the sum of three numbers is 750, find the

zloy xaker [14]

x+(x+8)+(x+100)=750
3x+108=750
3x=642
x=214
So your numbers are 214, 222 and 314

6 0

3 years ago

How do you factor out the coefficient of the variable

murzikaleks [220]

Factor out the GCF. Do not forget to include the GCF as part of your final answer. In this case, the three terms have a 3x in common, which leaves: Step 3: Multiply the leading coefficient and the constant, that is multiply the first and last numbers together.

4 0

3 years ago