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Aneli [31]
2 years ago
8

Solve the simultaneous equations below. 7x-6y = 30 2x+6y= 24

Mathematics
1 answer:
enot [183]2 years ago
6 0

Answer:

(x,y)—>(6,2)

Step-by-step explanation:

Add both equations to eliminate y

9x=54

x=6

plug x=6 into either equation

2(6)+6y=24

6y=24-12

y=12/6=2

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Answer:

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3 years ago
14. Ms. Brooks cell phone plan charges $27.00 a month for her phone. She is charged $0.15 per text she sends. She sends 78 texts
Licemer1 [7]

Answer:

$27.00 + 0.15t =

Step-by-step explanation:

8 0
3 years ago
Assume there are 365 days in a year.
Dahasolnce [82]
The chance of student 1's birthday being individual is 365/365 or 100%.
Then the chance of student 2's birthday being different is 364/365.
Then it's narrowed down to 363/365 for student 3 and so on until you get all 10 students.
If you multiply all these values together, the probability would come out at around 0.88305182223 or 0.88.

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4 0
3 years ago
What is the value of y,z,x​
ludmilkaskok [199]

Answer:

I don't really know

Step-by-step explanation:

I don't really know but if you want to find out math questions try this website called wolfram alpha. It's great with those type of stuff.

3 0
3 years ago
Last Sunday a certain store sold copies of Newspaper A for $1 and Newspaper B for 1.25. If r percent of the stores revenue came
Oksanka [162]

Answer:

Option 400p/500-p

Step-by-step explanation:

Let the number of newspaper A sold be 'x'

and the number of newspaper A sold be 'y'

Therefore,

Total revenue = $1x + $1.25y

Total newspapers sold = x + y

Therefore,

according to the question

r = \frac{x}{x + 1.25y}\times100 ..........(1)

and,

p =  \frac{x}{x + y}\times100

or

(x + y)p = 100x

or

y = \frac{x}{p}\times100-x

or

y = \frac{x(100-p)}{p}

substituting y in 1

r = \frac{x}{x + 1.25(\frac{x(100-p)}{p})}\times100

or

r = \frac{100p}{p+125-1.25p}

or

r = \frac{100p}{125-0.25p}

multiply and divide the RHS with 4

we get

r = (400p)÷(500-p)

hence,

Option 400p/500-p

3 0
4 years ago
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