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3 years ago

Help! I got 3 but it says its wrong. Anyone else have any answers that they solved for w/ proof?

Mathematics

1 answer:

lozanna [386]3 years ago

7 0

Answer:

Your answer is indeed correct. f(-8) = 3

Step-by-step explanation:

$f(x) = -x^{2} - 4x + 35\\f(-8) = -( -8)^{2} - 4(-8) + 35\\f(-8) = -64 + 32+ 35\\f(-8) = 3$

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Explain the difference between lateral and surface area below. If you are given the total surface area, then how could you deter

SVETLANKA909090 [29]

Lateral surface area is given as the area of all sides of a figure excluding the area of the base where as surface area is the sum of the areas of all faces of the solid.

Step-by-step explanation:

Lateral surface area is given as the area of all sides of a figure excluding the area of the base where as surface area is the sum of the areas of all faces of the solid.

If given total surface area, you can find lateral surface area by subtracting the area of the base from the surface area of the solid.

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Surface area and lateral surface area:brainly.com/question/14028871

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3 years ago

Solve the proportion forn 13= 16 n+11= 3n+6

Serggg [28]

The answer for your question is

N=2.5

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2 years ago

I am at a loss, I can’t think of the answer

aniked [119]

Answer:

To calculate the cylinder's volume we can use the formula to calculate this. We get pretty good number which gives us 75.4 Here's how I calculated it.

Answer: 75.4

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3 0

3 years ago

What is the perimeter of rhombus WXYZ?

oksian1 [2.3K]

Answer:

The perimeter of rhombus WXYZ is $4 \sqrt{13}$

Step-by-step explanation:

Step 1 :Finding length of XY

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 5

$x_2$ =3

$y_1$ = -1

$y_2$ =2

XY = $\sqrt{(3-5)^2 +(2 -(-1))^2}$

XY = $\sqrt{(3-5)^2 +(2 +1))^2}$

XY = $\sqrt{(-2)^2 +(3))^2}$

XY = $\sqrt{4 +9}$

XY = $\sqrt{(13)}$

Step 2 :Finding length of YZ

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 3

$x_2$ =5

$y_1$ = 2

$y_2$ =5

YZ = $\sqrt{(5-3)^2 +(5-2)^2}$

YZ = $\sqrt{(2)^2 +(3)^2}$

YZ = $\sqrt{4 +9}$

YZ = $\sqrt{(13)}$

Step 3 : :Finding length of ZW

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 5

$x_2$ =7

$y_1$ = 5

$y_2$ =2

ZW = $\sqrt{(7-5)^2 +(5-2)^2}$

ZW = $\sqrt{(2)^2 +(3)^2}$

ZW = $\sqrt{4 +9}$

ZW = $\sqrt{(13)}$

Step 4 :Finding length of WX

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 7

$x_2$ =5

$y_1$ = 2

$y_2$ = -1

WX = $\sqrt{(7-5)^2 +((-1)-2)^2}$

WX = $\sqrt{(2)^2 +(-3)^2}$

WX = $\sqrt{4 +9}$

WX = $\sqrt{(13)}$

Step 5: finding the perimeter of the rhombus

Perimeter= 4 X side

=> $4 \times \sqrt{13}$

=> $4 \sqrt{13}$

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3 years ago

Read 2 more answers

How is estimation helpful when adding and subtracting decimals?

alex41 [277]

Estimation is always helpful when it comes to math. By estimating, you will have a good idea with what the final answer should be before you actually get it. This way, you will hopefully be able to have a good sense of whether the answer is wrong

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3 years ago