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3 years ago

2(3C + 2d) = I don’t understand

Mathematics

2 answers:

Bezzdna [24]3 years ago

5 0

Answer:

i think its just saying times the numbers in (_) by 2 so 6c + 4d if so if not then sorry

Step-by-step explanation:

Lesechka [4]3 years ago

4 0

Answer: 6c + 4d

Step-by-step explanation:

The problem is in parentheses so you would distribute the 3 to each.

2x3c = 6c

2x2d = 4d

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Im completely stuck, can someone please help me out??

Rasek [7]

Answer:

Step-by-step explanation:

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3 years ago

Anna has leaned a ladder against the side of her house. If the ladder forms a 72º angle with the ground and rests against the ho

LuckyWell [14K]

Answer:

(A) 2 meter

Step-by-step explanation:

It is given that the ladder forms a 72º angle with the ground and rests against the house at a spot that is 6 meters high.

Let the measure of bottom of the ladder from the wall be x, then using the trigonometry, we have

$\frac{CB}{AB}=tan72^{\circ}$

$\frac{6}{x}=tan72^{\circ}$

$\frac{6}{x}=3.077$

$x=\frac{6}{3.077}$

$x=1.94$

$x$ ≈ $2m$

Thus, option A is correct.

6 0

3 years ago

Read 2 more answers

Can someone please help me on these two questions.

Valentin [98]

What are the questions

5 0

3 years ago

From a height of 50 meters above sea level on a cliff, two ships are sighted due west. The angles of depression are 61° and 28°.

Olenka [21]

Answer:

The ships are 66 meters apart.

Step-by-step explanation:

For the sake of convenience, let us label ships A and B

As shown in the figure, the distances to the ships from right triangles.

The distance to the ship A is $d_1$ and it is given by

$tan (61^o)= \dfrac{50}{d_1}$

$d_1=\dfrac{50}{tan (61^o)}$

$\boxed{d_1= 27.71m}$

And the distance to the ship B is $d_2$ and is given by

$tan (28^o)= \dfrac{50}{d_2}$

$d_2=\dfrac{50}{tan (28^o)}$

$\boxed{ d_2=94.04m}$

Therefore, the distance $d$ between the ships A and B is

$d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}$

In other words, the ships are 66 meters apart.

8 0

3 years ago

Read 2 more answers

When lava is expelled from a volcano, it temperature may vary from 700 degrees Celsius to 1200 degrees Celsius. Write an absolut

ValentinkaMS [17]

Answer:

Ix - 950°C I ≤ 250°C

Step-by-step explanation:

We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.

And that this temperature is x.

This means that the minimum value of x is 700°C while maximum of x is 1200 °C

Let's find the average of the two temperature limits given:

x_avg = (700 + 1200)/2 =

x_avg = 1900/2

x_avg = 950 °C

Now let's find the distance between the average and either maximum or minimum.

d_avg = (1200 - 700)/2

d_avg = 500/2

d_avg = 250°C.

Now absolute value equation will be in the form of;

Ix - x_avgI ≤ d_avg

Thus;

Ix - 950°C I ≤ 250°C

3 0

2 years ago