Question

I need help solving this plz

Answer 1

We can rewrite $cot(45^{\circ}+2\theta)$ as $tan(90^{\circ}-(45^{\circ}+2\theta)$ $\Rightarrow$ $cot(45^{\circ}+2\theta)$ equals to $tan(45^{\circ}-2\theta)$.

Now we need to take an $arctan$ of both sides.

$\theta = 45^{\circ}-2\theta+180n^{\circ} \\3\theta = 180n^{\circ}+45^{\circ} \\\theta = 60n^{\circ}+15^{\circ} \\\theta = 15^{\circ}$

Your answer is $15^{\circ}$.