F(x) = -2 and g(x) = 2x² + x-3, find (f +g)(x) .

Mathematics

1 answer:

tekilochka [14]2 years ago

8 0

Answer:

2x^2 + x - 5

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)=-2+2x^2 + x-3=2x^2 + x - 5

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A, C, D

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3 years ago

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The product of two positive integers is 176. One number is 5 more than the other. Find the smaller number.

svlad2 [7]

Hello from MrBillDoesMath!

Answer:

Discussion:

Let "n" be the smaller number. Then

n * (n+5) = 176.

My first reaction to this problem was to factor 176 in my head. That's 176 = 16 * 11 and 16 is 5 more than 11. So that's the solution!.... Now let's solve it using the brute force approach:

n(n+5) = 176 =>

n^2 + 5n - 176 = 0 => use the quadratic formula

n = ( -5 +\- sqrt( 5^2 - 4(1)(-176)) ) /2

= ( -5 +\- sqrt( 25 + 704) )/ 2

= ( -5 +\- sqrt (729) ) /2 => as sqrt(729) = 27

= (-5 +\- 27) / 2 =>

= (-5 + 27)/2 or ( -5 -27)/2 =>

= 22/2 or -32/2 =>

= 11 or -16

But -16 is not allowed as the question wants a positive value.

Thank you,

MrB

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3 years ago

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Use your calculator to select the best answer below:

bixtya [17]

Answer:

$-2\sqrt{a}$

Step-by-step explanation:

$\lim_{x \to a} \frac{a-x}{\sqrt{x} -\sqrt{a} } \\ =-\lim_{x \to a} \frac{x-a}{\sqrt{x} -\sqrt{a} } \\=-\lim_{x \to a} \frac{(\sqrt{x} -\sqrt{a})(\sqrt{x} +\sqrt{a})}{\sqrt{x} -\sqrt{a} } \\=- \lim_{x \to a} \sqrt{x} +\sqrt{a}\\=-2\sqrt{a}$